CF1796A.Typical Interview Problem
普及/提高-
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题目描述
The FB-string is formed as follows. Initially, it is empty. We go through all positive integers, starting from 1 , in ascending order, and do the following for each integer:
- if the current integer is divisible by 3 , append F to the end of the FB-string;
- if the current integer is divisible by 5 , append B to the end of the FB-string.
Note that if an integer is divisible by both 3 and 5 , we append F, and then B, not in the opposite order.
The first 10 characters of the FB-string are FBFFBFFBFB: the first F comes from the integer 3 , the next character (B) comes from 5 , the next F comes from the integer 6 , and so on. It's easy to see that this string is infinitely long. Let fi be the i -th character of FB-string; so, f1 is F, f2 is B, f3 is F, f4 is F, and so on.
You are given a string s , consisting of characters F and/or B. You have to determine whether it is a substring (contiguous subsequence) of the FB-string. In other words, determine if it is possible to choose two integers l and r ( 1≤l≤r ) so that the string flfl+1fl+2…fr is exactly s .
For example:
- FFB is a substring of the FB-string: if we pick l=3 and r=5 , the string f3f4f5 is exactly FFB;
- BFFBFFBF is a substring of the FB-string: if we pick l=2 and r=9 , the string f2f3f4…f9 is exactly BFFBFFBF;
- BBB is not a substring of the FB-string.
输入格式
The first line contains one integer t ( 1≤t≤2046 ) — the number of test cases.
Each test case consists of two lines. The first line contains one integer k ( 1≤k≤10 ) — the number of characters in s . The second line contains s , which is a string of exactly k characters. Each character of s is either F or B.
输出格式
For each test case, print YES if s is a substring of the FB-string, or NO otherwise.
You may print each letter in any case (YES, yes, Yes will all be recognized as positive answer, NO, no and nO will all be recognized as negative answer).
输入输出样例
输入#1
3 3 FFB 8 BFFBFFBF 3 BBB
输出#1
YES YES NO