CF1750C.Complementary XOR
普及/提高-
通过率:0%
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题目描述
You have two binary strings a and b of length n . You would like to make all the elements of both strings equal to 0 . Unfortunately, you can modify the contents of these strings using only the following operation:
- You choose two indices l and r ( 1≤l≤r≤n );
- For every i that respects l≤i≤r , change ai to the opposite. That is, ai:=1−ai ;
- For every i that respects either 1≤i<l or r<i≤n , change bi to the opposite. That is, bi:=1−bi .
Your task is to determine if this is possible, and if it is, to find such an appropriate chain of operations. The number of operations should not exceed n+5 . It can be proven that if such chain of operations exists, one exists with at most n+5 operations.
输入格式
Each test consists of multiple test cases. The first line contains a single integer t ( 1≤t≤105 ) — the number of test cases. The description of test cases follows.
The first line of each test case contains a single integer n ( 2≤n≤2⋅105 ) — the length of the strings.
The second line of each test case contains a binary string a , consisting only of characters 0 and 1, of length n .
The third line of each test case contains a binary string b , consisting only of characters 0 and 1, of length n .
It is guaranteed that sum of n over all test cases doesn't exceed 2⋅105 .
输出格式
For each testcase, print first "YES" if it's possible to make all the elements of both strings equal to 0 . Otherwise, print "NO". If the answer is "YES", on the next line print a single integer k ( 0≤k≤n+5 ) — the number of operations. Then k lines follows, each contains two integers l and r ( 1≤l≤r≤n ) — the description of the operation.
If there are several correct answers, print any of them.
输入输出样例
输入#1
5 3 010 101 2 11 10 4 1000 0011 2 10 10 3 111 111
输出#1
YES 1 2 2 NO NO YES 2 1 2 2 2 YES 2 1 1 2 3
说明/提示
In the first test case, we can perform one operation with l=2 and r=2 . So a2:=1−1=0 and string a became equal to 000. b1:=1−1=0 , b3:=1−1=0 and string b became equal to 000.
In the second and in the third test cases, it can be proven that it's impossible to make all elements of both strings equal to 0 .
In the fourth test case, we can perform an operation with l=1 and r=2 , then string a became equal to 01, and string b doesn't change. Then we perform an operation with l=2 and r=2 , then a2:=1−1=0 and b1=1−1=0 . So both of string a and b became equal to 00.
In the fifth test case, we can perform an operation with l=1 and r=1 . Then string a became equal to 011 and string b became equal to 100. Then we can perform an operation with l=2 and r=3 , so both of string a and b became equal to 000.