CF1764A.Doremy's Paint
普及/提高-
通过率:0%
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题目描述
Doremy has n buckets of paint which is represented by an array a of length n . Bucket i contains paint with color ai .
Let c(l,r) be the number of distinct elements in the subarray [al,al+1,…,ar] . Choose 2 integers l and r such that l≤r and r−l−c(l,r) is maximized.
输入格式
The input consists of multiple test cases. The first line contains a single integer t ( 1≤t≤104 ) — the number of test cases. The description of the test cases follows.
The first line of each test case contains a single integer n ( 1≤n≤105 ) — the length of the array a .
The second line of each test case contains n integers a1,a2,…,an ( 1≤ai≤n ).
It is guaranteed that the sum of n does not exceed 105 .
输出格式
For each test case, output l and r such that l≤r and r−l−c(l,r) is maximized.
If there are multiple solutions, you may output any.
输入输出样例
输入#1
7 5 1 3 2 2 4 5 1 2 3 4 5 4 2 1 2 1 3 2 3 3 2 2 2 1 1 9 9 8 5 2 1 1 2 3 3
输出#1
2 4 1 5 1 4 2 3 1 2 1 1 3 9
说明/提示
In the first test case, a=[1,3,2,2,4] .
- When l=1 and r=3 , c(l,r)=3 (there are 3 distinct elements in [1,3,2] ).
- When l=2 and r=4 , c(l,r)=2 (there are 2 distinct elements in [3,2,2] ).
It can be shown that choosing l=2 and r=4 maximizes the value of r−l−c(l,r) at 0 .
For the second test case, a=[1,2,3,4,5] .
- When l=1 and r=5 , c(l,r)=5 (there are 5 distinct elements in [1,2,3,4,5] ).
- When l=3 and r=3 , c(l,r)=1 (there is 1 distinct element in [3] ).
It can be shown that choosing l=1 and r=5 maximizes the value of r−l−c(l,r) at −1 . Choosing l=3 and r=3 is also acceptable.