CF1764E.Doremy's Number Line
普及/提高-
通过率:0%
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题目描述
Doremy has two arrays a and b of n integers each, and an integer k .
Initially, she has a number line where no integers are colored. She chooses a permutation p of [1,2,…,n] then performs n moves. On the i -th move she does the following:
- Pick an uncolored integer x on the number line such that either:
- x≤api ; or
- there exists a colored integer y such that y≤api and x≤y+bpi .
- Color integer x with color pi .
Determine if the integer k can be colored with color 1 .
输入格式
The input consists of multiple test cases. The first line contains a single integer t ( 1≤t≤104 ) — the number of test cases. The description of the test cases follows.
The first line contains two integers n and k ( 1≤n≤105 , 1≤k≤109 ).
Each of the following n lines contains two integers ai and bi ( 1≤ai,bi≤109 ).
It is guaranteed that the sum of n over all test cases does not exceed 105 .
输出格式
For each test case, output "YES" (without quotes) if the point k can be colored with color 1 . Otherwise, output "NO" (without quotes).
You can output "YES" and "NO" in any case (for example, strings "yEs", "yes" and "Yes" will be recognized as a positive response).
输入输出样例
输入#1
6 4 16 5 3 8 12 10 7 15 1 4 16 8 12 10 7 15 1 5 3 4 16 10 7 15 1 5 3 8 12 4 16 15 1 5 3 8 12 10 7 1 1000000000 500000000 500000000 2 1000000000 1 999999999 1 1
输出#1
NO YES YES YES NO YES
说明/提示
For the first test case, it is impossible to color point 16 with color 1 .
For the second test case, p=[2,1,3,4] is one possible choice, the detail is shown below.
- On the first move, pick x=8 and color it with color 2 since x=8 is uncolored and x≤a2 .
- On the second move, pick x=16 and color it with color 1 since there exists a colored point y=8 such that y≤a1 and x≤y+b1 .
- On the third move, pick x=0 and color it with color 3 since x=0 is uncolored and x≤a3 .
- On the forth move, pick x=−2 and color it with color 4 since x=−2 is uncolored and x≤a4 .
- In the end, point −2,0,8,16 are colored with color 4,3,2,1 , respectively.
For the third test case, p=[2,1,4,3] is one possible choice.
For the fourth test case, p=[2,3,4,1] is one possible choice.