CF1743E.FTL

Monocarp is playing a video game. In the game, he controls a spaceship and has to destroy an enemy spaceship.

Monocarp has two lasers installed on his spaceship. Both lasers $1$ and $2$ have two values:

• $p_i$ — the power of the laser;
• $t_i$ — the reload time of the laser.

When a laser is fully charged, Monocarp can either shoot it or wait for the other laser to charge and shoot both of them at the same time.

An enemy spaceship has $h$ durability and $s$ shield capacity. When Monocarp shoots an enemy spaceship, it receives $(P - s)$ damage (i. e. $(P - s)$ gets subtracted from its durability), where $P$ is the total power of the lasers that Monocarp shoots (i. e. $p_i$ if he only shoots laser $i$ and $p_1 + p_2$ if he shoots both lasers at the same time). An enemy spaceship is considered destroyed when its durability becomes $0$ or lower.

Initially, both lasers are zero charged.

What's the lowest amount of time it can take Monocarp to destroy an enemy spaceship?

The first line contains two integers $p_1$ and $t_1$ ( $2 \le p_1 \le 5000$ ; $1 \le t_1 \le 10^{12}$ ) — the power and the reload time of the first laser.

The second line contains two integers $p_2$ and $t_2$ ( $2 \le p_2 \le 5000$ ; $1 \le t_2 \le 10^{12}$ ) — the power and the reload time of the second laser.

The third line contains two integers $h$ and $s$ ( $1 \le h \le 5000$ ; $1 \le s < \min(p_1, p_2)$ ) — the durability and the shield capacity of an enemy spaceship. Note that the last constraint implies that Monocarp will always be able to destroy an enemy spaceship.

Print a single integer — the lowest amount of time it can take Monocarp to destroy an enemy spaceship.

In the first example, Monocarp waits for both lasers to charge, then shoots both lasers at $10$ , they deal $(5 + 4 - 1) = 8$ damage. Then he waits again and shoots lasers at $20$ , dealing $8$ more damage.

In the second example, Monocarp doesn't wait for the second laser to charge. He just shoots the first laser $25$ times, dealing $(10 - 9) = 1$ damage each time.