CF1717E.Madoka and The Best University

Madoka wants to enter to "Novosibirsk State University", but in the entrance exam she came across a very difficult task:

Given an integer $n$ , it is required to calculate $\sum{\operatorname{lcm}(c, \gcd(a, b))}$ , for all triples of positive integers $(a, b, c)$ , where $a + b + c = n$ .

In this problem $\gcd(x, y)$ denotes the greatest common divisor of $x$ and $y$ , and $\operatorname{lcm}(x, y)$ denotes the least common multiple of $x$ and $y$ .

Solve this problem for Madoka and help her to enter to the best university!

The first and the only line contains a single integer $n$ ( $3 \le n \le 10^5$ ).

Print exactly one interger — $\sum{\operatorname{lcm}(c, \gcd(a, b))}$ . Since the answer can be very large, then output it modulo $10^9 + 7$ .

In the first example, there is only one suitable triple $(1, 1, 1)$ . So the answer is $\operatorname{lcm}(1, \gcd(1, 1)) = \operatorname{lcm}(1, 1) = 1$ .

In the second example, $\operatorname{lcm}(1, \gcd(3, 1)) + \operatorname{lcm}(1, \gcd(2, 2)) + \operatorname{lcm}(1, \gcd(1, 3)) + \operatorname{lcm}(2, \gcd(2, 1)) + \operatorname{lcm}(2, \gcd(1, 2)) + \operatorname{lcm}(3, \gcd(1, 1)) = \operatorname{lcm}(1, 1) + \operatorname{lcm}(1, 2) + \operatorname{lcm}(1, 1) + \operatorname{lcm}(2, 1) + \operatorname{lcm}(2, 1) + \operatorname{lcm}(3, 1) = 1 + 2 + 1 + 2 + 2 + 3 = 11$