CF1718A2.Burenka and Traditions (hard version)
普及/提高-
通过率:0%
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题目描述
This is the hard version of this problem. The difference between easy and hard versions is only the constraints on ai and on n . You can make hacks only if both versions of the problem are solved.
Burenka is the crown princess of Buryatia, and soon she will become the n -th queen of the country. There is an ancient tradition in Buryatia — before the coronation, the ruler must show their strength to the inhabitants. To determine the strength of the n -th ruler, the inhabitants of the country give them an array of a of exactly n numbers, after which the ruler must turn all the elements of the array into zeros in the shortest time. The ruler can do the following two-step operation any number of times:
- select two indices l and r , so that 1≤l≤r≤n and a non-negative integer x , then
- for all l≤i≤r assign ai:=ai⊕x , where ⊕ denotes the bitwise XOR operation. It takes ⌈2r−l+1⌉ seconds to do this operation, where ⌈y⌉ denotes y rounded up to the nearest integer.
Help Burenka calculate how much time she will need.
输入格式
The first line contains a single integer t (1≤t≤500) — the number of test cases. The description of the test cases follows.
The first line of each test case contains a single integer n (1≤n≤105) - the size of the array
The second line of each test case contains n integers a1,a2,⋯,an (0≤ai<230) — elements of the array.
It is guaranteed that the sum of n in all tests does not exceed 105 .
输出格式
For each test case, output a single number — the minimum time that Burenka will need.
输入输出样例
输入#1
7 4 5 5 5 5 3 1 3 2 2 0 0 3 2 5 7 6 1 2 3 3 2 1 10 27 27 34 32 2 31 23 56 52 4 5 1822 1799 57 23 55
输出#1
2 2 0 2 4 7 4
说明/提示
In the first test case, Burenka can choose segment l=1 , r=4 , and x=5 . so it will fill the array with zeros in 2 seconds.
In the second test case, Burenka first selects segment l=1 , r=2 , and x=1 , after which a=[0,2,2] , and then the segment l=2 , r=3 , and x=2 , which fills the array with zeros. In total, Burenka will spend 2 seconds.