CF1692F.3SUM
普及/提高-
通过率:0%
AC君温馨提醒
该题目为【codeforces】题库的题目,您提交的代码将被提交至codeforces进行远程评测,并由ACGO抓取测评结果后进行展示。由于远程测评的测评机由其他平台提供,我们无法保证该服务的稳定性,若提交后无反应,请等待一段时间后再进行重试。
题目描述
Given an array a of positive integers with length n , determine if there exist three distinct indices i , j , k such that ai+aj+ak ends in the digit 3 .
输入格式
The first line contains an integer t ( 1≤t≤1000 ) — the number of test cases.
The first line of each test case contains an integer n ( 3≤n≤2⋅105 ) — the length of the array.
The second line of each test case contains n integers a1,a2,…,an ( 1≤ai≤109 ) — the elements of the array.
The sum of n across all test cases does not exceed 2⋅105 .
输出格式
Output t lines, each of which contains the answer to the corresponding test case. Output "YES" if there exist three distinct indices i , j , k satisfying the constraints in the statement, and "NO" otherwise.
You can output the answer in any case (for example, the strings "yEs", "yes", "Yes" and "YES" will be recognized as a positive answer).
输入输出样例
输入#1
6 4 20 22 19 84 4 1 11 1 2022 4 1100 1100 1100 1111 5 12 34 56 78 90 4 1 9 8 4 6 16 38 94 25 18 99
输出#1
YES YES NO NO YES YES
说明/提示
In the first test case, you can select i=1 , j=4 , k=3 . Then a1+a4+a3=20+84+19=123 , which ends in the digit 3 .
In the second test case, you can select i=1 , j=2 , k=3 . Then a1+a2+a3=1+11+1=13 , which ends in the digit 3 .
In the third test case, it can be proven that no such i , j , k exist. Note that i=4 , j=4 , k=4 is not a valid solution, since although a4+a4+a4=1111+1111+1111=3333 , which ends in the digit 3 , the indices need to be distinct.
In the fourth test case, it can be proven that no such i , j , k exist.
In the fifth test case, you can select i=4 , j=3 , k=1 . Then a4+a3+a1=4+8+1=13 , which ends in the digit 3 .
In the sixth test case, you can select i=1 , j=2 , k=6 . Then a1+a2+a6=16+38+99=153 , which ends in the digit 3 .