CF1662F.Antennas

普及/提高-

通过率:0%

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题目描述

There are nn equidistant antennas on a line, numbered from 11 to nn . Each antenna has a power rating, the power of the ii -th antenna is pip_i .

The ii -th and the jj -th antenna can communicate directly if and only if their distance is at most the minimum of their powers, i.e., ijmin(pi,pj)|i-j| \leq \min(p_i, p_j) . Sending a message directly between two such antennas takes 11 second.

What is the minimum amount of time necessary to send a message from antenna aa to antenna bb , possibly using other antennas as relays?

输入格式

Each test contains multiple test cases. The first line contains an integer tt ( 1t1000001\le t\le 100\,000 ) — the number of test cases. The descriptions of the tt test cases follow.

The first line of each test case contains three integers nn , aa , bb ( 1a,bn2000001 \leq a, b \leq n \leq 200\,000 ) — the number of antennas, and the origin and target antenna.

The second line contains nn integers p1,p2,,pnp_1, p_2, \dots, p_n ( 1pin1 \leq p_i \leq n ) — the powers of the antennas.

The sum of the values of nn over all test cases does not exceed 200000200\,000 .

输出格式

For each test case, print the number of seconds needed to trasmit a message from aa to bb . It can be shown that under the problem constraints, it is always possible to send such a message.

输入输出样例

  • 输入#1

    3
    10 2 9
    4 1 1 1 5 1 1 1 1 5
    1 1 1
    1
    3 1 3
    3 3 1

    输出#1

    4
    0
    2

说明/提示

In the first test case, we must send a message from antenna 22 to antenna 99 . A sequence of communications requiring 44 seconds, which is the minimum possible amount of time, is the following:

  • In 11 second we send the message from antenna 22 to antenna 11 . This is possible since 21min(1,4)=min(p2,p1)|2-1|\le \min(1, 4) = \min(p_2, p_1) .
  • In 11 second we send the message from antenna 11 to antenna 55 . This is possible since 15min(4,5)=min(p1,p5)|1-5|\le \min(4, 5) = \min(p_1, p_5) .
  • In 11 second we send the message from antenna 55 to antenna 1010 . This is possible since 510min(5,5)=min(p5,p10)|5-10|\le \min(5, 5) = \min(p_5, p_{10}) .
  • In 11 second we send the message from antenna 1010 to antenna 99 . This is possible since 109min(5,1)=min(p10,p9)|10-9|\le \min(5, 1) = \min(p_{10}, p_9) .
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