CF1620G.Subsequences Galore

普及/提高-

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题目描述

For a sequence of strings [t1,t2,,tm][t_1, t_2, \dots, t_m] , let's define the function f([t1,t2,,tm])f([t_1, t_2, \dots, t_m]) as the number of different strings (including the empty string) that are subsequences of at least one string tit_i . f([])=0f([]) = 0 (i. e. the number of such strings for an empty sequence is 00 ).

You are given a sequence of strings [s1,s2,,sn][s_1, s_2, \dots, s_n] . Every string in this sequence consists of lowercase Latin letters and is sorted (i. e., each string begins with several (maybe zero) characters a, then several (maybe zero) characters b, ..., ends with several (maybe zero) characters z).

For each of 2n2^n subsequences of [s1,s2,,sn][s_1, s_2, \dots, s_n] , calculate the value of the function ff modulo 998244353998244353 .

输入格式

The first line contains one integer nn ( 1n231 \le n \le 23 ) — the number of strings.

Then nn lines follow. The ii -th line contains the string sis_i ( 1si21041 \le |s_i| \le 2 \cdot 10^4 ), consisting of lowercase Latin letters. Each string sis_i is sorted.

输出格式

Since printing up to 2232^{23} integers would be really slow, you should do the following:

For each of the 2n2^n subsequences (which we denote as [si1,si2,,sik][s_{i_1}, s_{i_2}, \dots, s_{i_k}] ), calculate f([si1,si2,,sik])f([s_{i_1}, s_{i_2}, \dots, s_{i_k}]) , take it modulo 998244353998244353 , then multiply it by k(i1+i2++ik)k \cdot (i_1 + i_2 + \dots + i_k) . Print the XOR of all 2n2^n integers you get.

The indices i1,i2,,iki_1, i_2, \dots, i_k in the description of each subsequences are 11 -indexed (i. e. are from 11 to nn ).

输入输出样例

  • 输入#1

    3
    a
    b
    c

    输出#1

    92
  • 输入#2

    2
    aa
    a

    输出#2

    21
  • 输入#3

    2
    a
    a

    输出#3

    10
  • 输入#4

    2
    abcd
    aabb

    输出#4

    124
  • 输入#5

    3
    ddd
    aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
    aaaaaaaabbbbbbbbbbbcccccccccccciiiiiiiiiiiiiiiiiiiiiiooooooooooqqqqqqqqqqqqqqqqqqvvvvvzzzzzzzzzzzz

    输出#5

    15706243380
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