CF1623C.Balanced Stone Heaps
普及/提高-
通过率:0%
AC君温馨提醒
该题目为【codeforces】题库的题目,您提交的代码将被提交至codeforces进行远程评测,并由ACGO抓取测评结果后进行展示。由于远程测评的测评机由其他平台提供,我们无法保证该服务的稳定性,若提交后无反应,请等待一段时间后再进行重试。
题目描述
There are n heaps of stone. The i -th heap has hi stones. You want to change the number of stones in the heap by performing the following process once:
- You go through the heaps from the 3 -rd heap to the n -th heap, in this order.
- Let i be the number of the current heap.
- You can choose a number d ( 0≤3⋅d≤hi ), move d stones from the i -th heap to the (i−1) -th heap, and 2⋅d stones from the i -th heap to the (i−2) -th heap.
- So after that hi is decreased by 3⋅d , hi−1 is increased by d , and hi−2 is increased by 2⋅d .
- You can choose different or same d for different operations. Some heaps may become empty, but they still count as heaps.
What is the maximum number of stones in the smallest heap after the process?
输入格式
Each test contains multiple test cases. The first line contains the number of test cases t ( 1≤t≤2⋅105 ). Description of the test cases follows.
The first line of each test case contains a single integer n ( 3≤n≤2⋅105 ).
The second lines of each test case contains n integers h1,h2,h3,…,hn ( 1≤hi≤109 ).
It is guaranteed that the sum of n over all test cases does not exceed 2⋅105 .
输出格式
For each test case, print the maximum number of stones that the smallest heap can contain.
输入输出样例
输入#1
4 4 1 2 10 100 4 100 100 100 1 5 5 1 1 1 8 6 1 2 3 4 5 6
输出#1
7 1 1 3
说明/提示
In the first test case, the initial heap sizes are [1,2,10,100] . We can move the stones as follows.
- move 3 stones and 6 from the 3 -rd heap to the 2 -nd and 1 heap respectively. The heap sizes will be [7,5,1,100] ;
- move 6 stones and 12 stones from the last heap to the 3 -rd and 2 -nd heap respectively. The heap sizes will be [7,17,7,82] .
In the second test case, the last heap is 1 , and we can not increase its size.
In the third test case, it is better not to move any stones.
In the last test case, the final achievable configuration of the heaps can be [3,5,3,4,3,3] .