CF1631A.Min Max Swap
普及/提高-
通过率:0%
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题目描述
You are given two arrays a and b of n positive integers each. You can apply the following operation to them any number of times:
- Select an index i ( 1≤i≤n ) and swap ai with bi (i. e. ai becomes bi and vice versa).
Find the minimum possible value of max(a1,a2,…,an)⋅max(b1,b2,…,bn) you can get after applying such operation any number of times (possibly zero).
输入格式
The input consists of multiple test cases. The first line contains a single integer t ( 1≤t≤100 ) — the number of test cases. Description of the test cases follows.
The first line of each test case contains an integer n ( 1≤n≤100 ) — the length of the arrays.
The second line of each test case contains n integers a1,a2,…,an ( 1≤ai≤10000 ) where ai is the i -th element of the array a .
The third line of each test case contains n integers b1,b2,…,bn ( 1≤bi≤10000 ) where bi is the i -th element of the array b .
输出格式
For each test case, print a single integer, the minimum possible value of max(a1,a2,…,an)⋅max(b1,b2,…,bn) you can get after applying such operation any number of times.
输入输出样例
输入#1
3 6 1 2 6 5 1 2 3 4 3 2 2 5 3 3 3 3 3 3 3 2 1 2 2 1
输出#1
18 9 2
说明/提示
In the first test, you can apply the operations at indices 2 and 6 , then a=[1,4,6,5,1,5] and b=[3,2,3,2,2,2] , max(1,4,6,5,1,5)⋅max(3,2,3,2,2,2)=6⋅3=18 .
In the second test, no matter how you apply the operations, a=[3,3,3] and b=[3,3,3] will always hold, so the answer is max(3,3,3)⋅max(3,3,3)=3⋅3=9 .
In the third test, you can apply the operation at index 1 , then a=[2,2] , b=[1,1] , so the answer is max(2,2)⋅max(1,1)=2⋅1=2 .