CF1614B.Divan and a New Project

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题目描述

The company "Divan's Sofas" is planning to build n+1n + 1 different buildings on a coordinate line so that:

  • the coordinate of each building is an integer number;
  • no two buildings stand at the same point.

Let xix_i be the coordinate of the ii -th building. To get from the building ii to the building jj , Divan spends xixj|x_i - x_j| minutes, where y|y| is the absolute value of yy .

All buildings that Divan is going to build can be numbered from 00 to nn . The businessman will live in the building 00 , the new headquarters of "Divan's Sofas". In the first ten years after construction Divan will visit the ii -th building aia_i times, each time spending 2x0xi2 \cdot |x_0-x_i| minutes for walking.

Divan asks you to choose the coordinates for all n+1n + 1 buildings so that over the next ten years the businessman will spend as little time for walking as possible.

输入格式

Each test contains several test cases. The first line contains one integer number tt ( 1t1031 \le t \le 10^3 ) — the number of test cases.

The first line of each case contains an integer nn ( 1n21051 \le n \le 2 \cdot 10^5 ) — the number of buildings that "Divan's Sofas" is going to build, apart from the headquarters.

The second line contains the sequence a1,a2,,ana_1, a_2, \ldots, a_n ( 0ai1060 \le a_i \le 10^6 ), where aia_i is the number of visits to the ii -th building.

It is guaranteed that the sum of nn over all test cases does not exceed 21052 \cdot 10^5 .

输出格式

For each test case, on the first line print the number TT — the minimum time Divan will spend walking.

On the second line print the sequence x0,x1,,xnx_0, x_1, \ldots, x_n of n+1n + 1 integers, where xix_i ( 106xi106-10^6 \le x_i \le 10^6 ) is the selected coordinate of the ii -th building. It can be shown that an optimal answer exists with coordinates not exceeding 10610^6 .

If there are multiple answers, print any of them.

输入输出样例

  • 输入#1

    4
    3
    1 2 3
    5
    3 8 10 6 1
    5
    1 1 1 1 1
    1
    0

    输出#1

    14
    2 4 1 3
    78
    1 -1 0 2 3 4
    18
    3 6 1 5 2 4
    0
    1 2

说明/提示

Let's look at the first example.

Divan will visit the first building a1=1a_1 = 1 times, the second a2=2a_2 = 2 times and the third a3=3a_3 = 3 times. Then one of the optimal solution will be as follows:

  1. the headquarters is located in x0=2x_0 = 2 ;
  2. x1=4x_1 = 4 : Divan will spend 2x0x1a1=2241=42 \cdot |x_0-x_1| \cdot a_1 = 2 \cdot |2-4| \cdot 1 = 4 minutes walking to the first building;
  3. x2=1x_2 = 1 : Divan will spend 2x0x2a2=2212=42 \cdot |x_0-x_2| \cdot a_2 = 2 \cdot |2-1| \cdot 2 = 4 minutes walking to the second building;
  4. x3=3x_3 = 3 : Divan will spend 2x0x3a3=2233=62 \cdot |x_0-x_3| \cdot a_3 = 2 \cdot |2-3| \cdot 3 = 6 minutes walking to the third building.

In total, Divan will spend 4+4+6=144 + 4 + 6 = 14 minutes. It can be shown that it is impossible to arrange buildings so that the businessman spends less time.

Among others, x=[1,3,2,0]x = [1, 3, 2, 0] , x=[5,3,6,4]x = [-5, -3, -6, -4] are also correct answers for the first example.

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