CF1551A.Polycarp and Coins

普及/提高-

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题目描述

Polycarp must pay exactly nn burles at the checkout. He has coins of two nominal values: 11 burle and 22 burles. Polycarp likes both kinds of coins equally. So he doesn't want to pay with more coins of one type than with the other.

Thus, Polycarp wants to minimize the difference between the count of coins of 11 burle and 22 burles being used. Help him by determining two non-negative integer values c1c_1 and c2c_2 which are the number of coins of 11 burle and 22 burles, respectively, so that the total value of that number of coins is exactly nn (i. e. c1+2c2=nc_1 + 2 \cdot c_2 = n ), and the absolute value of the difference between c1c_1 and c2c_2 is as little as possible (i. e. you must minimize c1c2|c_1-c_2| ).

输入格式

The first line contains one integer tt ( 1t1041 \le t \le 10^4 ) — the number of test cases. Then tt test cases follow.

Each test case consists of one line. This line contains one integer nn ( 1n1091 \le n \le 10^9 ) — the number of burles to be paid by Polycarp.

输出格式

For each test case, output a separate line containing two integers c1c_1 and c2c_2 ( c1,c20c_1, c_2 \ge 0 ) separated by a space where c1c_1 is the number of coins of 11 burle and c2c_2 is the number of coins of 22 burles. If there are multiple optimal solutions, print any one.

输入输出样例

  • 输入#1

    6
    1000
    30
    1
    32
    1000000000
    5

    输出#1

    334 333
    10 10
    1 0
    10 11
    333333334 333333333
    1 2

说明/提示

The answer for the first test case is "334 333". The sum of the nominal values of all coins is 3341+3332=1000334 \cdot 1 + 333 \cdot 2 = 1000 , whereas 334333=1|334 - 333| = 1 . One can't get the better value because if c1c2=0|c_1 - c_2| = 0 , then c1=c2c_1 = c_2 and c11+c12=1000c_1 \cdot 1 + c_1 \cdot 2 = 1000 , but then the value of c1c_1 isn't an integer.

The answer for the second test case is "10 10". The sum of the nominal values is 101+102=3010 \cdot 1 + 10 \cdot 2 = 30 and 1010=0|10 - 10| = 0 , whereas there's no number having an absolute value less than 00 .

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