CF1557C.Moamen and XOR

普及/提高-

通过率:0%

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题目描述

Moamen and Ezzat are playing a game. They create an array aa of nn non-negative integers where every element is less than 2k2^k .

Moamen wins if a1&a2&a3&&ana1a2a3ana_1 \,\&\, a_2 \,\&\, a_3 \,\&\, \ldots \,\&\, a_n \ge a_1 \oplus a_2 \oplus a_3 \oplus \ldots \oplus a_n .

Here &\& denotes the bitwise AND operation, and \oplus denotes the bitwise XOR operation.

Please calculate the number of winning for Moamen arrays aa .

As the result may be very large, print the value modulo 10000000071\,000\,000\,007 ( 109+710^9 + 7 ).

输入格式

The first line contains a single integer tt ( 1t51 \le t \le 5 )— the number of test cases.

Each test case consists of one line containing two integers nn and kk ( 1n21051 \le n\le 2\cdot 10^5 , 0k21050 \le k \le 2\cdot 10^5 ).

输出格式

For each test case, print a single value — the number of different arrays that Moamen wins with.

Print the result modulo 10000000071\,000\,000\,007 ( 109+710^9 + 7 ).

输入输出样例

  • 输入#1

    3
    3 1
    2 1
    4 0

    输出#1

    5
    2
    1

说明/提示

In the first example, n=3n = 3 , k=1k = 1 . As a result, all the possible arrays are [0,0,0][0,0,0] , [0,0,1][0,0,1] , [0,1,0][0,1,0] , [1,0,0][1,0,0] , [1,1,0][1,1,0] , [0,1,1][0,1,1] , [1,0,1][1,0,1] , and [1,1,1][1,1,1] .

Moamen wins in only 55 of them: [0,0,0][0,0,0] , [1,1,0][1,1,0] , [0,1,1][0,1,1] , [1,0,1][1,0,1] , and [1,1,1][1,1,1] .

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