CF1515E.Phoenix and Computers

普及/提高-

通过率:0%

AC君温馨提醒

该题目为【codeforces】题库的题目,您提交的代码将被提交至codeforces进行远程评测,并由ACGO抓取测评结果后进行展示。由于远程测评的测评机由其他平台提供,我们无法保证该服务的稳定性,若提交后无反应,请等待一段时间后再进行重试。

题目描述

There are nn computers in a row, all originally off, and Phoenix wants to turn all of them on. He will manually turn on computers one at a time. At any point, if computer i1i-1 and computer i+1i+1 are both on, computer ii (2in1)(2 \le i \le n-1) will turn on automatically if it is not already on. Note that Phoenix cannot manually turn on a computer that already turned on automatically.

If we only consider the sequence of computers that Phoenix turns on manually, how many ways can he turn on all the computers? Two sequences are distinct if either the set of computers turned on manually is distinct, or the order of computers turned on manually is distinct. Since this number may be large, please print it modulo MM .

输入格式

The first line contains two integers nn and MM ( 3n4003 \le n \le 400 ; 108M10910^8 \le M \le 10^9 ) — the number of computers and the modulo. It is guaranteed that MM is prime.

输出格式

Print one integer — the number of ways to turn on the computers modulo MM .

输入输出样例

  • 输入#1

    3 100000007

    输出#1

    6
  • 输入#2

    4 100000007

    输出#2

    20
  • 输入#3

    400 234567899

    输出#3

    20914007

说明/提示

In the first example, these are the 66 orders in which Phoenix can turn on all computers:

  • [1,3][1,3] . Turn on computer 11 , then 33 . Note that computer 22 turns on automatically after computer 33 is turned on manually, but we only consider the sequence of computers that are turned on manually.
  • [3,1][3,1] . Turn on computer 33 , then 11 .
  • [1,2,3][1,2,3] . Turn on computer 11 , 22 , then 33 .
  • [2,1,3][2,1,3]
  • [2,3,1][2,3,1]
  • [3,2,1][3,2,1]
首页