CF1520F1.Guess the K-th Zero (Easy version)

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题目描述

This is an interactive problem.

This is an easy version of the problem. The difference from the hard version is that in the easy version t=1t=1 and the number of queries is limited to 2020 .

Polycarp is playing a computer game. In this game, an array consisting of zeros and ones is hidden. Polycarp wins if he guesses the position of the kk -th zero from the left tt times.

Polycarp can make no more than 2020 requests of the following type:

  • ? ll rr — find out the sum of all elements in positions from ll to rr ( 1lrn1 \le l \le r \le n ) inclusive.

In this (easy version) of the problem, this paragraph doesn't really make sense since t=1t=1 always. To make the game more interesting, each guessed zero turns into one and the game continues on the changed array. More formally, if the position of the kk -th zero was xx , then after Polycarp guesses this position, the xx -th element of the array will be replaced from 00 to 11 . Of course, this feature affects something only for t>1t>1 .

Help Polycarp win the game.

输入格式

输出格式

First, your program must read two integers nn and tt ( 1n21051 \le n \le 2 \cdot 10^5 , t=1t=1 ).

Then tt lines follow, each of which contains one integer kk ( 1kn1 \le k \le n ). It is guaranteed that at the moment of the request the array contains at least kk zeros. In order to get the next value of kk , you must output the answer for the current value of kk .

After that, you can make no more than 2020 requests.

Use the following format to output the answer (it is not a request, it doesn't count in 2020 ):

  • ! xx — position of the kk -th zero.

Positions in the array are numbered from left to right from 11 to nn inclusive.

After printing tt answers, your program should exit immediately.

In this task, the interactor is not adaptive. This means that within the same test, the hidden array and the queries do not change.

In case of an incorrect query, -1 will be displayed. When this value is received, your program must immediately exit normally (for example, by calling exit(0)), otherwise, the testing system may issue an arbitrary verdict.

If the number of requests is exceeded, the verdict wrong answer will be displayed.

Your solution may get the verdict Idleness limit exceeded if you don't print anything or forget to flush the output buffer.

To flush the output buffer, you need to do the following immediately after the query output and the end-of-line character:

  • fflush(stdout) or cout.flush() in C ++;
  • System.out.flush() in Java;
  • flush(output) in Pascal;
  • stdout.flush() in Python;
  • see the documentation for other languages.

Hacks

Use the following format for hacks:

On the first line print the string ss ( 1s21051 \le |s| \le 2 \cdot 10^5 ), consisting of zeros and ones, and an integer tt ( t=1t = 1 ) — hidden array and number of requests, respectively. In the next tt lines output the number kk ( 1ks1 \le k \le |s| ).

The hacked solution will not have direct access to the hidden array.

输入输出样例

  • 输入#1

    6 1
    2
    
    2
    
    1
    
    1
    
    0
    
    0

    输出#1

    ? 4 6
    
    ? 1 1
    
    ? 1 2
    
    ? 2 2
    
    ? 5 5
    
    ! 5

说明/提示

In the first test, the [1,0,1,1,0,1][1, 0, 1, 1, 0, 1] array is hidden. In this test k=2k=2 .

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