CF1462E2.Close Tuples (hard version)
普及/提高-
通过率:0%
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题目描述
This is the hard version of this problem. The only difference between the easy and hard versions is the constraints on k and m . In this version of the problem, you need to output the answer by modulo 109+7 .
You are given a sequence a of length n consisting of integers from 1 to n . The sequence may contain duplicates (i.e. some elements can be equal).
Find the number of tuples of m elements such that the maximum number in the tuple differs from the minimum by no more than k . Formally, you need to find the number of tuples of m indices i1<i2<…<im , such that
$$\max(a_{i_1}, a_{i_2}, \ldots, a_{i_m}) - \min(a_{i_1}, a_{i_2}, \ldots, a_{i_m}) \le k. $$ </p><p>For example, if $n=4$ , $m=3$ , $k=2$ , $a=\[1,2,4,3\]$ , then there are two such triples ( $i=1, j=2, z=4$ and $i=2, j=3, z=4$ ). If $n=4$ , $m=2$ , $k=1$ , $a=\[1,1,1,1\]$ , then all six possible pairs are suitable.</p><p><span class="tex-font-style-bf">As the result can be very large, you should print the value modulo $10^9 + 7$ (the remainder when divided by $10^9 + 7$$$).输入格式
The first line contains a single integer t ( 1≤t≤2⋅105 ) — the number of test cases. Then t test cases follow.
The first line of each test case contains three integers n , m , k ( 1≤n≤2⋅105 , 1≤m≤100 , 1≤k≤n ) — the length of the sequence a , number of elements in the tuples and the maximum difference of elements in the tuple.
The next line contains n integers a1,a2,…,an ( 1≤ai≤n ) — the sequence a .
It is guaranteed that the sum of n for all test cases does not exceed 2⋅105 .
输出格式
Output t answers to the given test cases. Each answer is the required number of tuples of m elements modulo 109+7 , such that the maximum value in the tuple differs from the minimum by no more than k .
输入输出样例
输入#1
4 4 3 2 1 2 4 3 4 2 1 1 1 1 1 1 1 1 1 10 4 3 5 6 1 3 2 9 8 1 2 4
输出#1
2 6 1 20