CF1472C.Long Jumps
普及/提高-
通过率:0%
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题目描述
Polycarp found under the Christmas tree an array a of n elements and instructions for playing with it:
- At first, choose index i ( 1≤i≤n ) — starting position in the array. Put the chip at the index i (on the value ai ).
- While i≤n , add ai to your score and move the chip ai positions to the right (i.e. replace i with i+ai ).
- If i>n , then Polycarp ends the game.
For example, if n=5 and a=[7,3,1,2,3] , then the following game options are possible:
- Polycarp chooses i=1 . Game process: i=1⟶+78 . The score of the game is: a1=7 .
- Polycarp chooses i=2 . Game process: i=2⟶+35⟶+38 . The score of the game is: a2+a5=6 .
- Polycarp chooses i=3 . Game process: i=3⟶+14⟶+26 . The score of the game is: a3+a4=3 .
- Polycarp chooses i=4 . Game process: i=4⟶+26 . The score of the game is: a4=2 .
- Polycarp chooses i=5 . Game process: i=5⟶+38 . The score of the game is: a5=3 .
Help Polycarp to find out the maximum score he can get if he chooses the starting index in an optimal way.
输入格式
The first line contains one integer t ( 1≤t≤104 ) — the number of test cases. Then t test cases follow.
The first line of each test case contains one integer n ( 1≤n≤2⋅105 ) — the length of the array a .
The next line contains n integers a1,a2,…,an ( 1≤ai≤109 ) — elements of the array a .
It is guaranteed that the sum of n over all test cases does not exceed 2⋅105 .
输出格式
For each test case, output on a separate line one number — the maximum score that Polycarp can get by playing the game on the corresponding array according to the instruction from the statement. Note that Polycarp chooses any starting position from 1 to n in such a way as to maximize his result.
输入输出样例
输入#1
4 5 7 3 1 2 3 3 2 1 4 6 2 1000 2 3 995 1 5 1 1 1 1 1
输出#1
7 6 1000 5
说明/提示
The first test case is explained in the statement.
In the second test case, the maximum score can be achieved by choosing i=1 .
In the third test case, the maximum score can be achieved by choosing i=2 .
In the fourth test case, the maximum score can be achieved by choosing i=1 .