CF1475A.Odd Divisor

普及/提高-

通过率:0%

AC君温馨提醒

该题目为【codeforces】题库的题目,您提交的代码将被提交至codeforces进行远程评测,并由ACGO抓取测评结果后进行展示。由于远程测评的测评机由其他平台提供,我们无法保证该服务的稳定性,若提交后无反应,请等待一段时间后再进行重试。

题目描述

You are given an integer nn . Check if nn has an odd divisor, greater than one (does there exist such a number xx ( x>1x > 1 ) that nn is divisible by xx and xx is odd).

For example, if n=6n=6 , then there is x=3x=3 . If n=4n=4 , then such a number does not exist.

输入格式

The first line contains one integer tt ( 1t1041 \le t \le 10^4 ) — the number of test cases. Then tt test cases follow.

Each test case contains one integer nn ( 2n10142 \le n \le 10^{14} ).

Please note, that the input for some test cases won't fit into 3232 -bit integer type, so you should use at least 6464 -bit integer type in your programming language.

输出格式

For each test case, output on a separate line:

  • "YES" if nn has an odd divisor, greater than one;
  • "NO" otherwise.

You can output "YES" and "NO" in any case (for example, the strings yEs, yes, Yes and YES will be recognized as positive).

输入输出样例

  • 输入#1

    6
    2
    3
    4
    5
    998244353
    1099511627776

    输出#1

    NO
    YES
    NO
    YES
    YES
    NO
首页