CF1437B.Reverse Binary Strings
普及/提高-
通过率:0%
AC君温馨提醒
该题目为【codeforces】题库的题目,您提交的代码将被提交至codeforces进行远程评测,并由ACGO抓取测评结果后进行展示。由于远程测评的测评机由其他平台提供,我们无法保证该服务的稳定性,若提交后无反应,请等待一段时间后再进行重试。
题目描述
You are given a string s of even length n . String s is binary, in other words, consists only of 0's and 1's.
String s has exactly 2n zeroes and 2n ones ( n is even).
In one operation you can reverse any substring of s . A substring of a string is a contiguous subsequence of that string.
What is the minimum number of operations you need to make string s alternating? A string is alternating if si=si+1 for all i . There are two types of alternating strings in general: 01010101... or 10101010...
输入格式
The first line contains a single integer t ( 1≤t≤1000 ) — the number of test cases.
The first line of each test case contains a single integer n ( 2≤n≤105 ; n is even) — the length of string s .
The second line of each test case contains a binary string s of length n ( si∈ {0, 1}). String s has exactly 2n zeroes and 2n ones.
It's guaranteed that the total sum of n over test cases doesn't exceed 105 .
输出格式
For each test case, print the minimum number of operations to make s alternating.
输入输出样例
输入#1
3 2 10 4 0110 8 11101000
输出#1
0 1 2
说明/提示
In the first test case, string 10 is already alternating.
In the second test case, we can, for example, reverse the last two elements of s and get: 0110 → 0101.
In the third test case, we can, for example, make the following two operations:
- 11101000 → 10101100;
- 10101100 → 10101010.