CF1407C.Chocolate Bunny

普及/提高-

通过率:0%

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题目描述

This is an interactive problem.

We hid from you a permutation pp of length nn , consisting of the elements from 11 to nn . You want to guess it. To do that, you can give us 2 different indices ii and jj , and we will reply with pimodpjp_{i} \bmod p_{j} (remainder of division pip_{i} by pjp_{j} ).

We have enough patience to answer at most 2n2 \cdot n queries, so you should fit in this constraint. Can you do it?

As a reminder, a permutation of length nn is an array consisting of nn distinct integers from 11 to nn in arbitrary order. For example, [2,3,1,5,4][2,3,1,5,4] is a permutation, but [1,2,2][1,2,2] is not a permutation ( 22 appears twice in the array) and [1,3,4][1,3,4] is also not a permutation ( n=3n=3 but there is 44 in the array).

输入格式

The only line of the input contains a single integer nn ( 1n1041 \le n \le 10^4 ) — length of the permutation.

输出格式

The interaction starts with reading nn .

Then you are allowed to make at most 2n2 \cdot n queries in the following way:

  • "? x y" ( 1x,yn,xy1 \le x, y \le n, x \ne y ).

After each one, you should read an integer kk , that equals pxmodpyp_x \bmod p_y .

When you have guessed the permutation, print a single line "! " (without quotes), followed by array pp and quit.

After printing a query do not forget to output end of line and flush the output. Otherwise, you will get Idleness limit exceeded. To do this, use:

  • fflush(stdout) or cout.flush() in C++;
  • System.out.flush() in Java;
  • flush(output) in Pascal;
  • stdout.flush() in Python;
  • see documentation for other languages.

Exit immediately after receiving "-1" and you will see Wrong answer verdict. Otherwise you can get an arbitrary verdict because your solution will continue to read from a closed stream.

Hack format

In the first line output nn ( 1n1041 \le n \le 10^4 ). In the second line print the permutation of nn integers p1,p2,,pnp_1, p_2, \ldots, p_n .

输入输出样例

  • 输入#1

    3
    
    1
    
    2
    
    1
    
    0

    输出#1

    ? 1 2
    
    ? 3 2
    
    ? 1 3
    
    ? 2 1
    
    ! 1 3 2
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