CF1372B.Omkar and Last Class of Math

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题目描述

In Omkar's last class of math, he learned about the least common multiple, or LCMLCM . LCM(a,b)LCM(a, b) is the smallest positive integer xx which is divisible by both aa and bb .

Omkar, having a laudably curious mind, immediately thought of a problem involving the LCMLCM operation: given an integer nn , find positive integers aa and bb such that a+b=na + b = n and LCM(a,b)LCM(a, b) is the minimum value possible.

Can you help Omkar solve his ludicrously challenging math problem?

输入格式

Each test contains multiple test cases. The first line contains the number of test cases tt ( 1t101 \leq t \leq 10 ). Description of the test cases follows.

Each test case consists of a single integer nn ( 2n1092 \leq n \leq 10^{9} ).

输出格式

For each test case, output two positive integers aa and bb , such that a+b=na + b = n and LCM(a,b)LCM(a, b) is the minimum possible.

输入输出样例

  • 输入#1

    3
    4
    6
    9

    输出#1

    2 2
    3 3
    3 6

说明/提示

For the first test case, the numbers we can choose are 1,31, 3 or 2,22, 2 . LCM(1,3)=3LCM(1, 3) = 3 and LCM(2,2)=2LCM(2, 2) = 2 , so we output 2 22 \ 2 .

For the second test case, the numbers we can choose are 1,51, 5 , 2,42, 4 , or 3,33, 3 . LCM(1,5)=5LCM(1, 5) = 5 , LCM(2,4)=4LCM(2, 4) = 4 , and LCM(3,3)=3LCM(3, 3) = 3 , so we output 3 33 \ 3 .

For the third test case, LCM(3,6)=6LCM(3, 6) = 6 . It can be shown that there are no other pairs of numbers which sum to 99 that have a lower LCMLCM .

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