CF1384B2.Koa and the Beach (Hard Version)

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题目描述

The only difference between easy and hard versions is on constraints. In this version constraints are higher. You can make hacks only if all versions of the problem are solved.

Koa the Koala is at the beach!

The beach consists (from left to right) of a shore, n+1n+1 meters of sea and an island at n+1n+1 meters from the shore.

She measured the depth of the sea at 1,2,,n1, 2, \dots, n meters from the shore and saved them in array dd . did_i denotes the depth of the sea at ii meters from the shore for 1in1 \le i \le n .

Like any beach this one has tide, the intensity of the tide is measured by parameter kk and affects all depths from the beginning at time t=0t=0 in the following way:

  • For a total of kk seconds, each second, tide increases all depths by 11 .
  • Then, for a total of kk seconds, each second, tide decreases all depths by 11 .
  • This process repeats again and again (ie. depths increase for kk seconds then decrease for kk seconds and so on ...). Formally, let's define 00 -indexed array p=[0,1,2,,k2,k1,k,k1,k2,,2,1]p = [0, 1, 2, \ldots, k - 2, k - 1, k, k - 1, k - 2, \ldots, 2, 1] of length 2k2k . At time tt ( 0t0 \le t ) depth at ii meters from the shore equals di+p[tmod2k]d_i + p[t \bmod 2k] ( tmod2kt \bmod 2k denotes the remainder of the division of tt by 2k2k ). Note that the changes occur instantaneously after each second, see the notes for better understanding.

At time t=0t=0 Koa is standing at the shore and wants to get to the island. Suppose that at some time tt ( 0t0 \le t ) she is at xx ( 0xn0 \le x \le n ) meters from the shore:

  • In one second Koa can swim 11 meter further from the shore ( xx changes to x+1x+1 ) or not swim at all ( xx stays the same), in both cases tt changes to t+1t+1 .
  • As Koa is a bad swimmer, the depth of the sea at the point where she is can't exceed ll at integer points of time (or she will drown). More formally, if Koa is at xx ( 1xn1 \le x \le n ) meters from the shore at the moment tt (for some integer t0t\ge 0 ), the depth of the sea at this point — dx+p[tmod2k]d_x + p[t \bmod 2k] — can't exceed ll . In other words, dx+p[tmod2k]ld_x + p[t \bmod 2k] \le l must hold always.
  • Once Koa reaches the island at n+1n+1 meters from the shore, she stops and can rest. Note that while Koa swims tide doesn't have effect on her (ie. she can't drown while swimming). Note that Koa can choose to stay on the shore for as long as she needs and neither the shore or the island are affected by the tide (they are solid ground and she won't drown there).

Koa wants to know whether she can go from the shore to the island. Help her!

输入格式

The first line of the input contains one integer tt ( 1t1041 \le t \le 10^4 ) — the number of test cases. Description of the test cases follows.

The first line of each test case contains three integers nn , kk and ll ( 1n3105;1k109;1l1091 \le n \le 3 \cdot 10^5; 1 \le k \le 10^9; 1 \le l \le 10^9 ) — the number of meters of sea Koa measured and parameters kk and ll .

The second line of each test case contains nn integers d1,d2,,dnd_1, d_2, \ldots, d_n ( 0di1090 \le d_i \le 10^9 ) — the depths of each meter of sea Koa measured.

It is guaranteed that the sum of nn over all test cases does not exceed 31053 \cdot 10^5 .

输出格式

For each test case:

Print Yes if Koa can get from the shore to the island, and No otherwise.

You may print each letter in any case (upper or lower).

输入输出样例

  • 输入#1

    7
    2 1 1
    1 0
    5 2 3
    1 2 3 2 2
    4 3 4
    0 2 4 3
    2 3 5
    3 0
    7 2 3
    3 0 2 1 3 0 1
    7 1 4
    4 4 3 0 2 4 2
    5 2 3
    1 2 3 2 2

    输出#1

    Yes
    No
    Yes
    Yes
    Yes
    No
    No

说明/提示

In the following ss denotes the shore, ii denotes the island, xx denotes distance from Koa to the shore, the underline denotes the position of Koa, and values in the array below denote current depths, affected by tide, at 1,2,,n1, 2, \dots, n meters from the shore.

In test case 11 we have n=2,k=1,l=1,p=[0,1]n = 2, k = 1, l = 1, p = [ 0, 1 ] .

Koa wants to go from shore (at x=0x = 0 ) to the island (at x=3x = 3 ). Let's describe a possible solution:

  • Initially at t=0t = 0 the beach looks like this: [s,1,0,i][\underline{s}, 1, 0, i] .
  • At t=0t = 0 if Koa would decide to swim to x=1x = 1 , beach would look like: [s,2,1,i][s, \underline{2}, 1, i] at t=1t = 1 , since 2>12 > 1 she would drown. So Koa waits 11 second instead and beach looks like [s,2,1,i][\underline{s}, 2, 1, i] at t=1t = 1 .
  • At t=1t = 1 Koa swims to x=1x = 1 , beach looks like [s,1,0,i][s, \underline{1}, 0, i] at t=2t = 2 . Koa doesn't drown because 111 \le 1 .
  • At t=2t = 2 Koa swims to x=2x = 2 , beach looks like [s,2,1,i][s, 2, \underline{1}, i] at t=3t = 3 . Koa doesn't drown because 111 \le 1 .
  • At t=3t = 3 Koa swims to x=3x = 3 , beach looks like [s,1,0,i][s, 1, 0, \underline{i}] at t=4t = 4 .
  • At t=4t = 4 Koa is at x=3x = 3 and she made it!

We can show that in test case 22 Koa can't get to the island.

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