CF1362C.Johnny and Another Rating Drop

普及/提高-

通过率:0%

AC君温馨提醒

该题目为【codeforces】题库的题目,您提交的代码将被提交至codeforces进行远程评测,并由ACGO抓取测评结果后进行展示。由于远程测评的测评机由其他平台提供,我们无法保证该服务的稳定性,若提交后无反应,请等待一段时间后再进行重试。

题目描述

The last contest held on Johnny's favorite competitive programming platform has been received rather positively. However, Johnny's rating has dropped again! He thinks that the presented tasks are lovely, but don't show the truth about competitors' skills.

The boy is now looking at the ratings of consecutive participants written in a binary system. He thinks that the more such ratings differ, the more unfair is that such people are next to each other. He defines the difference between two numbers as the number of bit positions, where one number has zero, and another has one (we suppose that numbers are padded with leading zeros to the same length). For example, the difference of 5=10125 = 101_2 and 14=1110214 = 1110_2 equals to 33 , since 01010101 and 11101110 differ in 33 positions. Johnny defines the unfairness of the contest as the sum of such differences counted for neighboring participants.

Johnny has just sent you the rating sequence and wants you to find the unfairness of the competition. You have noticed that you've got a sequence of consecutive integers from 00 to nn . That's strange, but the boy stubbornly says that everything is right. So help him and find the desired unfairness for received numbers.

输入格式

The input consists of multiple test cases. The first line contains one integer tt ( 1t100001 \leq t \leq 10\,000 ) — the number of test cases. The following tt lines contain a description of test cases.

The first and only line in each test case contains a single integer nn ( 1n1018)1 \leq n \leq 10^{18}) .

输出格式

Output tt lines. For each test case, you should output a single line with one integer — the unfairness of the contest if the rating sequence equals to 00 , 11 , ..., n1n - 1 , nn .

输入输出样例

  • 输入#1

    5
    5
    7
    11
    1
    2000000000000

    输出#1

    8
    11
    19
    1
    3999999999987

说明/提示

For n=5n = 5 we calculate unfairness of the following sequence (numbers from 00 to 55 written in binary with extra leading zeroes, so they all have the same length):

  • 000000
  • 001001
  • 010010
  • 011011
  • 100100
  • 101101

The differences are equal to 11 , 22 , 11 , 33 , 11 respectively, so unfairness is equal to 1+2+1+3+1=81 + 2 + 1 + 3 + 1 = 8 .

首页