CF1354A.Alarm Clock

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AC君温馨提醒

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题目描述

Polycarp has spent the entire day preparing problems for you. Now he has to sleep for at least aa minutes to feel refreshed.

Polycarp can only wake up by hearing the sound of his alarm. So he has just fallen asleep and his first alarm goes off in bb minutes.

Every time Polycarp wakes up, he decides if he wants to sleep for some more time or not. If he's slept for less than aa minutes in total, then he sets his alarm to go off in cc minutes after it is reset and spends dd minutes to fall asleep again. Otherwise, he gets out of his bed and proceeds with the day.

If the alarm goes off while Polycarp is falling asleep, then he resets his alarm to go off in another cc minutes and tries to fall asleep for dd minutes again.

You just want to find out when will Polycarp get out of his bed or report that it will never happen.

Please check out the notes for some explanations of the example.

输入格式

The first line contains one integer tt ( 1t10001 \le t \le 1000 ) — the number of testcases.

The only line of each testcase contains four integers a,b,c,da, b, c, d ( 1a,b,c,d1091 \le a, b, c, d \le 10^9 ) — the time Polycarp has to sleep for to feel refreshed, the time before the first alarm goes off, the time before every succeeding alarm goes off and the time Polycarp spends to fall asleep.

输出格式

For each test case print one integer. If Polycarp never gets out of his bed then print -1. Otherwise, print the time it takes for Polycarp to get out of his bed.

输入输出样例

  • 输入#1

    7
    10 3 6 4
    11 3 6 4
    5 9 4 10
    6 5 2 3
    1 1 1 1
    3947465 47342 338129 123123
    234123843 13 361451236 361451000

    输出#1

    27
    27
    9
    -1
    1
    6471793
    358578060125049

说明/提示

In the first testcase Polycarp wakes up after 33 minutes. He only rested for 33 minutes out of 1010 minutes he needed. So after that he sets his alarm to go off in 66 minutes and spends 44 minutes falling asleep. Thus, he rests for 22 more minutes, totaling in 3+2=53+2=5 minutes of sleep. Then he repeats the procedure three more times and ends up with 1111 minutes of sleep. Finally, he gets out of his bed. He spent 33 minutes before the first alarm and then reset his alarm four times. The answer is 3+46=273+4 \cdot 6 = 27 .

The second example is almost like the first one but Polycarp needs 1111 minutes of sleep instead of 1010 . However, that changes nothing because he gets 1111 minutes with these alarm parameters anyway.

In the third testcase Polycarp wakes up rested enough after the first alarm. Thus, the answer is b=9b=9 .

In the fourth testcase Polycarp wakes up after 55 minutes. Unfortunately, he keeps resetting his alarm infinitely being unable to rest for even a single minute :(

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