A1526.[COCI-2013_2014-contest5]#3 LADICE

Mirko has N items (labeled with numbers from 1 to N) and L drawers (labeled with numbers from 1 to L). All items are currently scattered throughout his room, so he decided to clean them up. Each drawer can contain one item, and in order to make it easier for Mirko to find them later, he has determined in advance exactly two drawers (Ai and Bi ) for each item i.
Mirko stores the items in order from 1 to N using the first rule he can apply:

1. If the drawer Ai is empty, he stores the item i in that drawer
2. If the drawer Bi is empty, he stores the item i in that drawer
3. Try to move the item from Ai to its other drawer; if that one's filled too, try moving that item to its other drawer, and so on until you either succeed or get back to a previously seen drawer. In case of success, store the item i in the drawer Ai . In case of failure, continue to next rule.
4. Try moving the item from Bi to its other drawer; if that one's filled too, try moving that item to its other drawer, and so on until you either succeed or get back to a previously seen drawer. In case of success, store the item i in the drawer Bi . In case of failure, continue to next rule.
5. Give up and throw away the item i.
   For given pairs of drawers for each item, determine which items will be stored and which will be thrown away.

The first line of input consists of two integers, N and L (1 ≤ N, L ≤ 300 000), the number of items and the number of drawers.
Each of the following N lines contains two integers: Ai and Bi (1 ≤ Ai and Bi ≤ L), pair of drawers corresponding to the item i. The numbers Ai and Bi will be different.

For each item, respectively, output where it ends up.
In case the item is stored successfully, output "LADICA" (without quotes, Croatian word for drawer).
In case the item is thrown away, output "SMECE" (without quotes, Croatian word for trash).

In test cases worth 50% of total points, both N and L will be lesser than 2000.

Clarification of the first example: The first item goes to drawer 1 by rule 1). The second item goes to
drawer 3 by rule 2). The third item goes to drawer 2 by rule 2).
For the fourth and fifth item, both drawers are already taken and cannot be emptied.
Clarification of the second example: The first six items go into drawers 1, 3, 5, 7, 9, 2 (respectively),
by rule 1). For the seventh item, applying the rule 3), we try to move the item in drawer 1 to drawer 2,
the item in drawer 2 to drawer 3, the item in drawer 3 to drawer 4, which we succeed because the
drawer is empty.
The eighth item goes to drawer 8 which was empty from the beginning.
For the ninth item, applying the rule 3), we try to move the item in drawer 7 to drawer 8, the item in
drawer 8 to drawer 2, the item in drawer 2 to drawer 1, the item in drawer 1 to drawer 5, the item in
drawer 5 to drawer 6, which we succeed because the drawer is empty.