CF1288B.Yet Another Meme Problem

普及/提高-

通过率:0%

AC君温馨提醒

该题目为【codeforces】题库的题目,您提交的代码将被提交至codeforces进行远程评测,并由ACGO抓取测评结果后进行展示。由于远程测评的测评机由其他平台提供,我们无法保证该服务的稳定性,若提交后无反应,请等待一段时间后再进行重试。

题目描述

Try guessing the statement from this picture http://tiny.cc/ogyoiz.

You are given two integers AA and BB , calculate the number of pairs (a,b)(a, b) such that 1aA1 \le a \le A , 1bB1 \le b \le B , and the equation ab+a+b=conc(a,b)a \cdot b + a + b = conc(a, b) is true; conc(a,b)conc(a, b) is the concatenation of aa and bb (for example, conc(12,23)=1223conc(12, 23) = 1223 , conc(100,11)=10011conc(100, 11) = 10011 ). aa and bb should not contain leading zeroes.

输入格式

The first line contains tt ( 1t1001 \le t \le 100 ) — the number of test cases.

Each test case contains two integers AA and BB (1A,B109)(1 \le A, B \le 10^9) .

输出格式

Print one integer — the number of pairs (a,b)(a, b) such that 1aA1 \le a \le A , 1bB1 \le b \le B , and the equation ab+a+b=conc(a,b)a \cdot b + a + b = conc(a, b) is true.

输入输出样例

  • 输入#1

    3
    1 11
    4 2
    191 31415926

    输出#1

    1
    0
    1337

说明/提示

There is only one suitable pair in the first test case: a=1a = 1 , b=9b = 9 ( 1+9+19=191 + 9 + 1 \cdot 9 = 19 ).

首页