CF1264D2.Beautiful Bracket Sequence (hard version)

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题目描述

This is the hard version of this problem. The only difference is the limit of nn - the length of the input string. In this version, 1n1061 \leq n \leq 10^6 .

Let's define a correct bracket sequence and its depth as follow:

  • An empty string is a correct bracket sequence with depth 00 .
  • If "s" is a correct bracket sequence with depth dd then "(s)" is a correct bracket sequence with depth d+1d + 1 .
  • If "s" and "t" are both correct bracket sequences then their concatenation "st" is a correct bracket sequence with depth equal to the maximum depth of ss and tt .

For a (not necessarily correct) bracket sequence ss , we define its depth as the maximum depth of any correct bracket sequence induced by removing some characters from ss (possibly zero). For example: the bracket sequence $s = $ "())(())" has depth 22 , because by removing the third character we obtain a correct bracket sequence "()(())" with depth 22 .

Given a string aa consists of only characters '(', ')' and '?'. Consider all (not necessarily correct) bracket sequences obtained by replacing all characters '?' in aa by either '(' or ')'. Calculate the sum of all the depths of all these bracket sequences. As this number can be large, find it modulo 998244353998244353 .

Hacks in this problem can be done only if easy and hard versions of this problem was solved.

输入格式

The only line contains a non-empty string consist of only '(', ')' and '?'. The length of the string is at most 10610^6 .

输出格式

Print the answer modulo 998244353998244353 in a single line.

输入输出样例

  • 输入#1

    ??
    

    输出#1

    1
    
  • 输入#2

    (?(?))
    

    输出#2

    9
    

说明/提示

In the first test case, we can obtain 44 bracket sequences by replacing all characters '?' with either '(' or ')':

  • "((". Its depth is 00 ;
  • "))". Its depth is 00 ;
  • ")(". Its depth is 00 ;
  • "()". Its depth is 11 .

So, the answer is 1=0+0+0+11 = 0 + 0 + 0 + 1 .

In the second test case, we can obtain 44 bracket sequences by replacing all characters '?' with either '(' or ')':

  • "(((())". Its depth is 22 ;
  • "()()))". Its depth is 22 ;
  • "((()))". Its depth is 33 ;
  • "()(())". Its depth is 22 .

So, the answer is 9=2+2+3+29 = 2 + 2 + 3 + 2 .

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