CF1264D1.Beautiful Bracket Sequence (easy version)
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题目描述
This is the easy version of this problem. The only difference is the limit of n - the length of the input string. In this version, 1≤n≤2000 . The hard version of this challenge is not offered in the round for the second division.
Let's define a correct bracket sequence and its depth as follow:
- An empty string is a correct bracket sequence with depth 0 .
- If "s" is a correct bracket sequence with depth d then "(s)" is a correct bracket sequence with depth d+1 .
- If "s" and "t" are both correct bracket sequences then their concatenation "st" is a correct bracket sequence with depth equal to the maximum depth of s and t .
For a (not necessarily correct) bracket sequence s , we define its depth as the maximum depth of any correct bracket sequence induced by removing some characters from s (possibly zero). For example: the bracket sequence $s = $ "())(())" has depth 2 , because by removing the third character we obtain a correct bracket sequence "()(())" with depth 2 .
Given a string a consists of only characters '(', ')' and '?'. Consider all (not necessarily correct) bracket sequences obtained by replacing all characters '?' in a by either '(' or ')'. Calculate the sum of all the depths of all these bracket sequences. As this number can be large, find it modulo 998244353 .
Hacks in this problem in the first division can be done only if easy and hard versions of this problem was solved.
输入格式
The only line contains a non-empty string consist of only '(', ')' and '?'. The length of the string is at most 2000 .
输出格式
Print the answer modulo 998244353 in a single line.
输入输出样例
输入#1
??
输出#1
1
输入#2
(?(?))
输出#2
9
说明/提示
In the first test case, we can obtain 4 bracket sequences by replacing all characters '?' with either '(' or ')':
- "((". Its depth is 0 ;
- "))". Its depth is 0 ;
- ")(". Its depth is 0 ;
- "()". Its depth is 1 .
So, the answer is 1=0+0+0+1 .
In the second test case, we can obtain 4 bracket sequences by replacing all characters '?' with either '(' or ')':
- "(((())". Its depth is 2 ;
- "()()))". Its depth is 2 ;
- "((()))". Its depth is 3 ;
- "()(())". Its depth is 2 .
So, the answer is 9=2+2+3+2 .