CF1249D2.Too Many Segments (hard version)
普及/提高-
通过率:0%
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题目描述
The only difference between easy and hard versions is constraints.
You are given n segments on the coordinate axis OX . Segments can intersect, lie inside each other and even coincide. The i -th segment is [li;ri] ( li≤ri ) and it covers all integer points j such that li≤j≤ri .
The integer point is called bad if it is covered by strictly more than k segments.
Your task is to remove the minimum number of segments so that there are no bad points at all.
输入格式
The first line of the input contains two integers n and k ( 1≤k≤n≤2⋅105 ) — the number of segments and the maximum number of segments by which each integer point can be covered.
The next n lines contain segments. The i -th line contains two integers li and ri ( 1≤li≤ri≤2⋅105 ) — the endpoints of the i -th segment.
输出格式
In the first line print one integer m ( 0≤m≤n ) — the minimum number of segments you need to remove so that there are no bad points.
In the second line print m distinct integers p1,p2,…,pm ( 1≤pi≤n ) — indices of segments you remove in any order. If there are multiple answers, you can print any of them.
输入输出样例
输入#1
7 2 11 11 9 11 7 8 8 9 7 8 9 11 7 9
输出#1
3 4 6 7
输入#2
5 1 29 30 30 30 29 29 28 30 30 30
输出#2
3 1 4 5
输入#3
6 1 2 3 3 3 2 3 2 2 2 3 2 3
输出#3
4 1 3 5 6