CF1223C.Save the Nature

普及/提高-

通过率:0%

AC君温馨提醒

该题目为【codeforces】题库的题目,您提交的代码将被提交至codeforces进行远程评测,并由ACGO抓取测评结果后进行展示。由于远程测评的测评机由其他平台提供,我们无法保证该服务的稳定性,若提交后无反应,请等待一段时间后再进行重试。

题目描述

You are an environmental activist at heart but the reality is harsh and you are just a cashier in a cinema. But you can still do something!

You have nn tickets to sell. The price of the ii -th ticket is pip_i . As a teller, you have a possibility to select the order in which the tickets will be sold (i.e. a permutation of the tickets). You know that the cinema participates in two ecological restoration programs applying them to the order you chose:

  • The x%x\% of the price of each the aa -th sold ticket ( aa -th, 2a2a -th, 3a3a -th and so on) in the order you chose is aimed for research and spreading of renewable energy sources.
  • The y%y\% of the price of each the bb -th sold ticket ( bb -th, 2b2b -th, 3b3b -th and so on) in the order you chose is aimed for pollution abatement.

If the ticket is in both programs then the (x+y)%(x + y) \% are used for environmental activities. Also, it's known that all prices are multiples of 100100 , so there is no need in any rounding.

For example, if you'd like to sell tickets with prices [400,100,300,200][400, 100, 300, 200] and the cinema pays 10%10\% of each 22 -nd sold ticket and 20%20\% of each 33 -rd sold ticket, then arranging them in order [100,200,300,400][100, 200, 300, 400] will lead to contribution equal to 1000+2000.1+3000.2+4000.1=120100 \cdot 0 + 200 \cdot 0.1 + 300 \cdot 0.2 + 400 \cdot 0.1 = 120 . But arranging them in order [100,300,400,200][100, 300, 400, 200] will lead to 1000+3000.1+4000.2+2000.1=130100 \cdot 0 + 300 \cdot 0.1 + 400 \cdot 0.2 + 200 \cdot 0.1 = 130 .

Nature can't wait, so you decided to change the order of tickets in such a way, so that the total contribution to programs will reach at least kk in minimum number of sold tickets. Or say that it's impossible to do so. In other words, find the minimum number of tickets which are needed to be sold in order to earn at least kk .

输入格式

The first line contains a single integer qq ( 1q1001 \le q \le 100 ) — the number of independent queries. Each query consists of 55 lines.

The first line of each query contains a single integer nn ( 1n21051 \le n \le 2 \cdot 10^5 ) — the number of tickets.

The second line contains nn integers p1,p2,,pnp_1, p_2, \dots, p_n ( 100pi109100 \le p_i \le 10^9 , pimod100=0p_i \bmod 100 = 0 ) — the corresponding prices of tickets.

The third line contains two integers xx and aa ( 1x1001 \le x \le 100 , x+y100x + y \le 100 , 1an1 \le a \le n ) — the parameters of the first program.

The fourth line contains two integers yy and bb ( 1y1001 \le y \le 100 , x+y100x + y \le 100 , 1bn1 \le b \le n ) — the parameters of the second program.

The fifth line contains single integer kk ( 1k10141 \le k \le 10^{14} ) — the required total contribution.

It's guaranteed that the total number of tickets per test doesn't exceed 21052 \cdot 10^5 .

输出格式

Print qq integers — one per query.

For each query, print the minimum number of tickets you need to sell to make the total ecological contribution of at least kk if you can sell tickets in any order.

If the total contribution can not be achieved selling all the tickets, print 1-1 .

输入输出样例

  • 输入#1

    4
    1
    100
    50 1
    49 1
    100
    8
    100 200 100 200 100 200 100 100
    10 2
    15 3
    107
    3
    1000000000 1000000000 1000000000
    50 1
    50 1
    3000000000
    5
    200 100 100 100 100
    69 5
    31 2
    90
    

    输出#1

    -1
    6
    3
    4
    

说明/提示

In the first query the total contribution is equal to 50+49=99<10050 + 49 = 99 < 100 , so it's impossible to gather enough money.

In the second query you can rearrange tickets in a following way: [100,100,200,200,100,200,100,100][100, 100, 200, 200, 100, 200, 100, 100] and the total contribution from the first 66 tickets is equal to 1000+1000.1+2000.15+2000.1+1000+2000.25=10+30+20+50=110100 \cdot 0 + 100 \cdot 0.1 + 200 \cdot 0.15 + 200 \cdot 0.1 + 100 \cdot 0 + 200 \cdot 0.25 = 10 + 30 + 20 + 50 = 110 .

In the third query the full price of each ticket goes to the environmental activities.

In the fourth query you can rearrange tickets as [100,200,100,100,100][100, 200, 100, 100, 100] and the total contribution from the first 44 tickets is 1000+2000.31+1000+1000.31=62+31=93100 \cdot 0 + 200 \cdot 0.31 + 100 \cdot 0 + 100 \cdot 0.31 = 62 + 31 = 93 .

首页