CF1237D.Balanced Playlist
普及/提高-
通过率:0%
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题目描述
Your favorite music streaming platform has formed a perfectly balanced playlist exclusively for you. The playlist consists of n tracks numbered from 1 to n . The playlist is automatic and cyclic: whenever track i finishes playing, track i+1 starts playing automatically; after track n goes track 1 .
For each track i , you have estimated its coolness ai . The higher ai is, the cooler track i is.
Every morning, you choose a track. The playlist then starts playing from this track in its usual cyclic fashion. At any moment, you remember the maximum coolness x of already played tracks. Once you hear that a track with coolness strictly less than 2x (no rounding) starts playing, you turn off the music immediately to keep yourself in a good mood.
For each track i , find out how many tracks you will listen to before turning off the music if you start your morning with track i , or determine that you will never turn the music off. Note that if you listen to the same track several times, every time must be counted.
输入格式
The first line contains a single integer n ( 2≤n≤105 ), denoting the number of tracks in the playlist.
The second line contains n integers a1,a2,…,an ( 1≤ai≤109 ), denoting coolnesses of the tracks.
输出格式
Output n integers c1,c2,…,cn , where ci is either the number of tracks you will listen to if you start listening from track i or −1 if you will be listening to music indefinitely.
输入输出样例
输入#1
4 11 5 2 7
输出#1
1 1 3 2
输入#2
4 3 2 5 3
输出#2
5 4 3 6
输入#3
3 4 3 6
输出#3
-1 -1 -1
说明/提示
In the first example, here is what will happen if you start with...
- track 1 : listen to track 1 , stop as a2<2a1 .
- track 2 : listen to track 2 , stop as a3<2a2 .
- track 3 : listen to track 3 , listen to track 4 , listen to track 1 , stop as a2<2max(a3,a4,a1) .
- track 4 : listen to track 4 , listen to track 1 , stop as a2<2max(a4,a1) .
In the second example, if you start with track 4 , you will listen to track 4 , listen to track 1 , listen to track 2 , listen to track 3 , listen to track 4 again, listen to track 1 again, and stop as a2<2max(a4,a1,a2,a3,a4,a1) . Note that both track 1 and track 4 are counted twice towards the result.