CF1213D1.Equalizing by Division (easy version)

普及/提高-

通过率:0%

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题目描述

The only difference between easy and hard versions is the number of elements in the array.

You are given an array aa consisting of nn integers. In one move you can choose any aia_i and divide it by 22 rounding down (in other words, in one move you can set ai:=ai2a_i := \lfloor\frac{a_i}{2}\rfloor ).

You can perform such an operation any (possibly, zero) number of times with any aia_i .

Your task is to calculate the minimum possible number of operations required to obtain at least kk equal numbers in the array.

Don't forget that it is possible to have ai=0a_i = 0 after some operations, thus the answer always exists.

输入格式

The first line of the input contains two integers nn and kk ( 1kn501 \le k \le n \le 50 ) — the number of elements in the array and the number of equal numbers required.

The second line of the input contains nn integers a1,a2,,ana_1, a_2, \dots, a_n ( 1ai21051 \le a_i \le 2 \cdot 10^5 ), where aia_i is the ii -th element of aa .

输出格式

Print one integer — the minimum possible number of operations required to obtain at least kk equal numbers in the array.

输入输出样例

  • 输入#1

    5 3
    1 2 2 4 5
    

    输出#1

    1
    
  • 输入#2

    5 3
    1 2 3 4 5
    

    输出#2

    2
    
  • 输入#3

    5 3
    1 2 3 3 3
    

    输出#3

    0
    
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