CF1213D1.Equalizing by Division (easy version)
普及/提高-
通过率:0%
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题目描述
The only difference between easy and hard versions is the number of elements in the array.
You are given an array a consisting of n integers. In one move you can choose any ai and divide it by 2 rounding down (in other words, in one move you can set ai:=⌊2ai⌋ ).
You can perform such an operation any (possibly, zero) number of times with any ai .
Your task is to calculate the minimum possible number of operations required to obtain at least k equal numbers in the array.
Don't forget that it is possible to have ai=0 after some operations, thus the answer always exists.
输入格式
The first line of the input contains two integers n and k ( 1≤k≤n≤50 ) — the number of elements in the array and the number of equal numbers required.
The second line of the input contains n integers a1,a2,…,an ( 1≤ai≤2⋅105 ), where ai is the i -th element of a .
输出格式
Print one integer — the minimum possible number of operations required to obtain at least k equal numbers in the array.
输入输出样例
输入#1
5 3 1 2 2 4 5
输出#1
1
输入#2
5 3 1 2 3 4 5
输出#2
2
输入#3
5 3 1 2 3 3 3
输出#3
0