CF1158D.Winding polygonal line

Vasya has $n$ different points $A_1, A_2, \ldots A_n$ on the plane. No three of them lie on the same line He wants to place them in some order $A_{p_1}, A_{p_2}, \ldots, A_{p_n}$ , where $p_1, p_2, \ldots, p_n$ — some permutation of integers from $1$ to $n$ .

After doing so, he will draw oriented polygonal line on these points, drawing oriented segments from each point to the next in the chosen order. So, for all $1 \leq i \leq n-1$ he will draw oriented segment from point $A_{p_i}$ to point $A_{p_{i+1}}$ . He wants to make this polygonal line satisfying $2$ conditions:

• it will be non-self-intersecting, so any $2$ segments which are not neighbors don't have common points.
• it will be winding.

Vasya has a string $s$ , consisting of $(n-2)$ symbols "L" or "R". Let's call an oriented polygonal line winding, if its $i$ -th turn left, if $s_i = $ "L" and right, if $s_i = $ "R". More formally: $i$ -th turn will be in point $A_{p_{i+1}}$ , where oriented segment from point $A_{p_i}$ to point $A_{p_{i+1}}$ changes to oriented segment from point $A_{p_{i+1}}$ to point $A_{p_{i+2}}$ . Let's define vectors $\overrightarrow{v_1} = \overrightarrow{A_{p_i} A_{p_{i+1}}}$ and $\overrightarrow{v_2} = \overrightarrow{A_{p_{i+1}} A_{p_{i+2}}}$ . Then if in order to rotate the vector $\overrightarrow{v_1}$ by the smallest possible angle, so that its direction coincides with the direction of the vector $\overrightarrow{v_2}$ we need to make a turn counterclockwise, then we say that $i$ -th turn is to the left, and otherwise to the right. For better understanding look at this pictures with some examples of turns:

There are left turns on this picture There are right turns on this pictureYou are given coordinates of the points $A_1, A_2, \ldots A_n$ on the plane and string $s$ . Find a permutation $p_1, p_2, \ldots, p_n$ of the integers from $1$ to $n$ , such that the polygonal line, drawn by Vasya satisfy two necessary conditions.

The first line contains one integer $n$ — the number of points ( $3 \leq n \leq 2000$ ). Next $n$ lines contains two integers $x_i$ and $y_i$ , divided by space — coordinates of the point $A_i$ on the plane ( $-10^9 \leq x_i, y_i \leq 10^9$ ). The last line contains a string $s$ consisting of symbols "L" and "R" with length $(n-2)$ . It is guaranteed that all points are different and no three points lie at the same line.

If the satisfying permutation doesn't exists, print $-1$ . In the other case, print $n$ numbers $p_1, p_2, \ldots, p_n$ — the permutation which was found ( $1 \leq p_i \leq n$ and all $p_1, p_2, \ldots, p_n$ are different). If there exists more than one solution, you can find any.

This is the picture with the polygonal line from the $1$ test:

As we see, this polygonal line is non-self-intersecting and winding, because the turn in point $2$ is left.

This is the picture with the polygonal line from the $2$ test: