CF1119A.Ilya and a Colorful Walk

普及/提高-

通过率:0%

AC君温馨提醒

该题目为【codeforces】题库的题目,您提交的代码将被提交至codeforces进行远程评测,并由ACGO抓取测评结果后进行展示。由于远程测评的测评机由其他平台提供,我们无法保证该服务的稳定性,若提交后无反应,请等待一段时间后再进行重试。

题目描述

Ilya lives in a beautiful city of Chordalsk.

There are nn houses on the street Ilya lives, they are numerated from 11 to nn from left to right; the distance between every two neighboring houses is equal to 11 unit. The neighboring houses are 11 and 22 , 22 and 33 , ..., n1n-1 and nn . The houses nn and 11 are not neighboring.

The houses are colored in colors c1,c2,,cnc_1, c_2, \ldots, c_n so that the ii -th house is colored in the color cic_i . Everyone knows that Chordalsk is not boring, so there are at least two houses colored in different colors.

Ilya wants to select two houses ii and jj so that 1i<jn1 \leq i < j \leq n , and they have different colors: cicjc_i \neq c_j . He will then walk from the house ii to the house jj the distance of (ji)(j-i) units.

Ilya loves long walks, so he wants to choose the houses so that the distance between them is the maximum possible.

Help Ilya, find this maximum possible distance.

输入格式

The first line contains a single integer nn ( 3n3000003 \leq n \leq 300\,000 ) — the number of cities on the street.

The second line contains nn integers c1,c2,,cnc_1, c_2, \ldots, c_n ( 1cin1 \leq c_i \leq n ) — the colors of the houses.

It is guaranteed that there is at least one pair of indices ii and jj so that 1i<jn1 \leq i < j \leq n and cicjc_i \neq c_j .

输出格式

Print a single integer — the maximum possible distance Ilya can walk.

输入输出样例

  • 输入#1

    5
    1 2 3 2 3
    

    输出#1

    4
    
  • 输入#2

    3
    1 2 1
    

    输出#2

    1
    
  • 输入#3

    7
    1 1 3 1 1 1 1
    

    输出#3

    4
    

说明/提示

In the first example the optimal way is to walk from the first house to the last one, where Ilya can walk the distance of 51=45-1 = 4 units.

In the second example the optimal way is to either walk from the first house to the second or from the second to the third. Both these ways have the distance of 11 unit.

In the third example the optimal way is to walk from the third house to the last one, where Ilya can walk the distance of 73=47-3 = 4 units.

首页