CF1120C.Compress String

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题目描述

Suppose you are given a string ss of length nn consisting of lowercase English letters. You need to compress it using the smallest possible number of coins.

To compress the string, you have to represent ss as a concatenation of several non-empty strings: s=t1t2tks = t_{1} t_{2} \ldots t_{k} . The ii -th of these strings should be encoded with one of the two ways:

  • if ti=1|t_{i}| = 1 , meaning that the current string consists of a single character, you can encode it paying aa coins;
  • if tit_{i} is a substring of t1t2ti1t_{1} t_{2} \ldots t_{i - 1} , then you can encode it paying bb coins.

A string xx is a substring of a string yy if xx can be obtained from yy by deletion of several (possibly, zero or all) characters from the beginning and several (possibly, zero or all) characters from the end.

So your task is to calculate the minimum possible number of coins you need to spend in order to compress the given string ss .

输入格式

The first line contains three positive integers, separated by spaces: nn , aa and bb ( 1n,a,b50001 \leq n, a, b \leq 5000 ) — the length of the string, the cost to compress a one-character string and the cost to compress a string that appeared before.

The second line contains a single string ss , consisting of nn lowercase English letters.

输出格式

Output a single integer — the smallest possible number of coins you need to spend to compress ss .

输入输出样例

  • 输入#1

    3 3 1
    aba
    

    输出#1

    7
    
  • 输入#2

    4 1 1
    abcd
    

    输出#2

    4
    
  • 输入#3

    4 10 1
    aaaa
    

    输出#3

    12
    

说明/提示

In the first sample case, you can set t1=t_{1} = 'a', t2=t_{2} = 'b', t3=t_{3} = 'a' and pay 3+3+1=73 + 3 + 1 = 7 coins, since t3t_{3} is a substring of t1t2t_{1}t_{2} .

In the second sample, you just need to compress every character by itself.

In the third sample, you set t1=t2=t_{1} = t_{2} = 'a', t3=t_{3} = 'aa' and pay 10+1+1=1210 + 1 + 1 = 12 coins, since t2t_{2} is a substring of t1t_{1} and t3t_{3} is a substring of t1t2t_{1} t_{2} .

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