CF1096E.The Top Scorer
普及/提高-
通过率:0%
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题目描述
Hasan loves playing games and has recently discovered a game called TopScore. In this soccer-like game there are p players doing penalty shoot-outs. Winner is the one who scores the most. In case of ties, one of the top-scorers will be declared as the winner randomly with equal probability.
They have just finished the game and now are waiting for the result. But there's a tiny problem! The judges have lost the paper of scores! Fortunately they have calculated sum of the scores before they get lost and also for some of the players they have remembered a lower bound on how much they scored. However, the information about the bounds is private, so Hasan only got to know his bound.
According to the available data, he knows that his score is at least r and sum of the scores is s .
Thus the final state of the game can be represented in form of sequence of p integers a1,a2,…,ap ( 0≤ai ) — player's scores. Hasan is player number 1 , so a1≥r . Also a1+a2+⋯+ap=s . Two states are considered different if there exists some position i such that the value of ai differs in these states.
Once again, Hasan doesn't know the exact scores (he doesn't know his exact score as well). So he considers each of the final states to be equally probable to achieve.
Help Hasan find the probability of him winning.
It can be shown that it is in the form of QP where P and Q are non-negative integers and Q=0 , P≤Q . Report the value of P⋅Q−1(mod998244353) .
输入格式
The only line contains three integers p , s and r ( 1≤p≤100 , 0≤r≤s≤5000 ) — the number of players, the sum of scores of all players and Hasan's score, respectively.
输出格式
Print a single integer — the probability of Hasan winning.
It can be shown that it is in the form of QP where P and Q are non-negative integers and Q=0 , P≤Q . Report the value of P⋅Q−1(mod998244353) .
输入输出样例
输入#1
2 6 3
输出#1
124780545
输入#2
5 20 11
输出#2
1
输入#3
10 30 10
输出#3
85932500
说明/提示
In the first example Hasan can score 3 , 4 , 5 or 6 goals. If he scores 4 goals or more than he scores strictly more than his only opponent. If he scores 3 then his opponent also scores 3 and Hasan has a probability of 21 to win the game. Thus, overall he has the probability of 87 to win.
In the second example even Hasan's lower bound on goal implies him scoring more than any of his opponents. Thus, the resulting probability is 1 .