CF1097G.Vladislav and a Great Legend

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题目描述

A great legend used to be here, but some troll hacked Codeforces and erased it. Too bad for us, but in the troll society he earned a title of an ultimate-greatest-over troll. At least for them, it's something good. And maybe a formal statement will be even better for us?

You are given a tree TT with nn vertices numbered from 11 to nn . For every non-empty subset XX of vertices of TT , let f(X)f(X) be the minimum number of edges in the smallest connected subtree of TT which contains every vertex from XX .

You're also given an integer kk . You need to compute the sum of (f(X))k(f(X))^k among all non-empty subsets of vertices, that is:

X{1,2,,n},X(f(X))k.\sum\limits_{X \subseteq \{1, 2,\: \dots \:, n\},\, X \neq \varnothing} (f(X))^k.

输入格式

The first line contains two integers nn and kk ( 2n1052 \leq n \leq 10^5 , 1k2001 \leq k \leq 200 ) — the size of the tree and the exponent in the sum above.

Each of the following n1n - 1 lines contains two integers aia_i and bib_i ( 1ai,bin1 \leq a_i,b_i \leq n ) — the indices of the vertices connected by the corresponding edge.

It is guaranteed, that the edges form a tree.

输出格式

Print a single integer — the requested sum modulo 109+710^9 + 7 .

输入输出样例

  • 输入#1

    4 1
    1 2
    2 3
    2 4
    

    输出#1

    21
    
  • 输入#2

    4 2
    1 2
    2 3
    2 4
    

    输出#2

    45
    
  • 输入#3

    5 3
    1 2
    2 3
    3 4
    4 5
    

    输出#3

    780
    

说明/提示

In the first two examples, the values of ff are as follows:

f({1})=0f(\{1\}) = 0

f({2})=0f(\{2\}) = 0

f({1,2})=1f(\{1, 2\}) = 1

f({3})=0f(\{3\}) = 0

f({1,3})=2f(\{1, 3\}) = 2

f({2,3})=1f(\{2, 3\}) = 1

f({1,2,3})=2f(\{1, 2, 3\}) = 2

f({4})=0f(\{4\}) = 0

f({1,4})=2f(\{1, 4\}) = 2

f({2,4})=1f(\{2, 4\}) = 1

f({1,2,4})=2f(\{1, 2, 4\}) = 2

f({3,4})=2f(\{3, 4\}) = 2

f({1,3,4})=3f(\{1, 3, 4\}) = 3

f({2,3,4})=2f(\{2, 3, 4\}) = 2

f({1,2,3,4})=3f(\{1, 2, 3, 4\}) = 3

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