CF1101C.Division and Union

普及/提高-

通过率:0%

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题目描述

There are nn segments [li,ri][l_i, r_i] for 1in1 \le i \le n . You should divide all segments into two non-empty groups in such way that there is no pair of segments from different groups which have at least one common point, or say that it's impossible to do it. Each segment should belong to exactly one group.

To optimize testing process you will be given multitest.

输入格式

The first line contains one integer TT ( 1T500001 \le T \le 50000 ) — the number of queries. Each query contains description of the set of segments. Queries are independent.

First line of each query contains single integer nn ( 2n1052 \le n \le 10^5 ) — number of segments. It is guaranteed that n\sum{n} over all queries does not exceed 10510^5 .

The next nn lines contains two integers lil_i , rir_i per line ( 1liri21051 \le l_i \le r_i \le 2 \cdot 10^5 ) — the ii -th segment.

输出格式

For each query print nn integers t1,t2,,tnt_1, t_2, \dots, t_n ( ti{1,2}t_i \in \{1, 2\} ) — for each segment (in the same order as in the input) tit_i equals 11 if the ii -th segment will belongs to the first group and 22 otherwise.

If there are multiple answers, you can print any of them. If there is no answer, print 1-1 .

输入输出样例

  • 输入#1

    3
    2
    5 5
    2 3
    3
    3 5
    2 3
    2 3
    3
    3 3
    4 4
    5 5
    

    输出#1

    2 1 
    -1
    1 1 2 
    

说明/提示

In the first query the first and the second segments should be in different groups, but exact numbers don't matter.

In the second query the third segment intersects with the first and the second segments, so they should be in the same group, but then the other group becomes empty, so answer is 1-1 .

In the third query we can distribute segments in any way that makes groups non-empty, so any answer of 66 possible is correct.

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