CF1101C.Division and Union
普及/提高-
通过率:0%
AC君温馨提醒
该题目为【codeforces】题库的题目,您提交的代码将被提交至codeforces进行远程评测,并由ACGO抓取测评结果后进行展示。由于远程测评的测评机由其他平台提供,我们无法保证该服务的稳定性,若提交后无反应,请等待一段时间后再进行重试。
题目描述
There are n segments [li,ri] for 1≤i≤n . You should divide all segments into two non-empty groups in such way that there is no pair of segments from different groups which have at least one common point, or say that it's impossible to do it. Each segment should belong to exactly one group.
To optimize testing process you will be given multitest.
输入格式
The first line contains one integer T ( 1≤T≤50000 ) — the number of queries. Each query contains description of the set of segments. Queries are independent.
First line of each query contains single integer n ( 2≤n≤105 ) — number of segments. It is guaranteed that ∑n over all queries does not exceed 105 .
The next n lines contains two integers li , ri per line ( 1≤li≤ri≤2⋅105 ) — the i -th segment.
输出格式
For each query print n integers t1,t2,…,tn ( ti∈{1,2} ) — for each segment (in the same order as in the input) ti equals 1 if the i -th segment will belongs to the first group and 2 otherwise.
If there are multiple answers, you can print any of them. If there is no answer, print −1 .
输入输出样例
输入#1
3 2 5 5 2 3 3 3 5 2 3 2 3 3 3 3 4 4 5 5
输出#1
2 1 -1 1 1 2
说明/提示
In the first query the first and the second segments should be in different groups, but exact numbers don't matter.
In the second query the third segment intersects with the first and the second segments, so they should be in the same group, but then the other group becomes empty, so answer is −1 .
In the third query we can distribute segments in any way that makes groups non-empty, so any answer of 6 possible is correct.