CF1082D.Maximum Diameter Graph

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题目描述

Graph constructive problems are back! This time the graph you are asked to build should match the following properties.

The graph is connected if and only if there exists a path between every pair of vertices.

The diameter (aka "longest shortest path") of a connected undirected graph is the maximum number of edges in the shortest path between any pair of its vertices.

The degree of a vertex is the number of edges incident to it.

Given a sequence of nn integers a1,a2,,ana_1, a_2, \dots, a_n construct a connected undirected graph of nn vertices such that:

  • the graph contains no self-loops and no multiple edges;
  • the degree did_i of the ii -th vertex doesn't exceed aia_i (i.e. diaid_i \le a_i );
  • the diameter of the graph is maximum possible.

Output the resulting graph or report that no solution exists.

输入格式

The first line contains a single integer nn ( 3n5003 \le n \le 500 ) — the number of vertices in the graph.

The second line contains nn integers a1,a2,,ana_1, a_2, \dots, a_n ( 1ain11 \le a_i \le n - 1 ) — the upper limits to vertex degrees.

输出格式

Print "NO" if no graph can be constructed under the given conditions.

Otherwise print "YES" and the diameter of the resulting graph in the first line.

The second line should contain a single integer mm — the number of edges in the resulting graph.

The ii -th of the next mm lines should contain two integers vi,uiv_i, u_i ( 1vi,uin1 \le v_i, u_i \le n , viuiv_i \neq u_i ) — the description of the ii -th edge. The graph should contain no multiple edges — for each pair (x,y)(x, y) you output, you should output no more pairs (x,y)(x, y) or (y,x)(y, x) .

输入输出样例

  • 输入#1

    3
    2 2 2
    

    输出#1

    YES 2
    2
    1 2
    2 3
    
  • 输入#2

    5
    1 4 1 1 1
    

    输出#2

    YES 2
    4
    1 2
    3 2
    4 2
    5 2
    
  • 输入#3

    3
    1 1 1
    

    输出#3

    NO
    

说明/提示

Here are the graphs for the first two example cases. Both have diameter of 22 .

d1=1a1=2d_1 = 1 \le a_1 = 2 d2=2a2=2d_2 = 2 \le a_2 = 2

d3=1a3=2d_3 = 1 \le a_3 = 2

d1=1a1=1d_1 = 1 \le a_1 = 1 d2=4a2=4d_2 = 4 \le a_2 = 4

d3=1a3=1d_3 = 1 \le a_3 = 1

d4=1a4=1d_4 = 1 \le a_4 = 1

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