CF1088E.Ehab and a component choosing problem

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题目描述

You're given a tree consisting of nn nodes. Every node uu has a weight aua_u . You want to choose an integer kk (1kn)(1 \le k \le n) and then choose kk connected components of nodes that don't overlap (i.e every node is in at most 1 component). Let the set of nodes you chose be ss . You want to maximize:

$$\frac{\sum\limits_{u \in s} a_u}{k} $$ </p><p>In other words, you want to maximize the sum of weights of nodes in $s$ divided by the number of connected components you chose. Also, if there are several solutions, you want to <span class="tex-font-style-bf">maximize $k$$$. Note that adjacent nodes can belong to different components. Refer to the third sample.

输入格式

The first line contains the integer nn (1n3105)(1 \le n \le 3 \cdot 10^5) , the number of nodes in the tree.

The second line contains nn space-separated integers a1a_1 , a2a_2 , \dots , ana_n (ai109)(|a_i| \le 10^9) , the weights of the nodes.

The next n1n-1 lines, each contains 2 space-separated integers uu and vv (1u,vn)(1 \le u,v \le n) which means there's an edge between uu and vv .

输出格式

Print the answer as a non-reduced fraction represented by 2 space-separated integers. The fraction itself should be maximized and if there are several possible ways, you should maximize the denominator. See the samples for a better understanding.

输入输出样例

  • 输入#1

    3
    1 2 3
    1 2
    1 3
    

    输出#1

    6 1
  • 输入#2

    1
    -2
    

    输出#2

    -2 1
  • 输入#3

    3
    -1 -1 -1
    1 2
    2 3
    

    输出#3

    -3 3
  • 输入#4

    3
    -1 -2 -1
    1 2
    1 3
    

    输出#4

    -2 2

说明/提示

A connected component is a set of nodes such that for any node in the set, you can reach all other nodes in the set passing only nodes in the set.

In the first sample, it's optimal to choose the whole tree.

In the second sample, you only have one choice (to choose node 1) because you can't choose 0 components.

In the third sample, notice that we could've, for example, chosen only node 1, or node 1 and node 3, or even the whole tree, and the fraction would've had the same value (-1), but we want to maximize kk .

In the fourth sample, we'll just choose nodes 1 and 3.

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