CF1031E.Triple Flips

普及/提高-

通过率:0%

AC君温馨提醒

该题目为【codeforces】题库的题目,您提交的代码将被提交至codeforces进行远程评测,并由ACGO抓取测评结果后进行展示。由于远程测评的测评机由其他平台提供,我们无法保证该服务的稳定性,若提交后无反应,请等待一段时间后再进行重试。

题目描述

You are given an array aa of length nn that consists of zeros and ones.

You can perform the following operation multiple times. The operation consists of two steps:

  1. Choose three integers 1x<y<zn1 \le x < y < z \le n , that form an arithmetic progression ( yx=zyy - x = z - y ).
  2. Flip the values ax,ay,aza_x, a_y, a_z (i.e. change 11 to 00 , change 00 to 11 ).

Determine if it is possible to make all elements of the array equal to zero. If yes, print the operations that lead the the all-zero state. Your solution should not contain more than (n3+12)(\lfloor \frac{n}{3} \rfloor + 12) operations. Here q\lfloor q \rfloor denotes the number qq rounded down. We can show that it is possible to make all elements equal to zero in no more than this number of operations whenever it is possible to do so at all.

输入格式

The first line contains a single integer nn ( 3n1053 \le n \le 10^5 ) — the length of the array.

The second line contains nn integers a1,a2,,ana_1, a_2, \ldots, a_n ( 0ai10 \le a_i \le 1 ) — the elements of the array.

输出格式

Print "YES" (without quotes) if the answer exists, otherwise print "NO" (without quotes). You can print each letter in any case (upper or lower).

If there is an answer, in the second line print an integer mm ( 0m(n3+12)0 \le m \le (\lfloor \frac{n}{3} \rfloor + 12) ) — the number of operations in your answer.

After that in ( i+2i + 2 )-th line print the ii -th operations — the integers xi,yi,zix_i, y_i, z_i . You can print them in arbitrary order.

输入输出样例

  • 输入#1

    5
    1 1 0 1 1
    

    输出#1

    YES
    2
    1 3 5
    2 3 4
    
  • 输入#2

    3
    0 1 0
    

    输出#2

    NO
    

说明/提示

In the first sample the shown output corresponds to the following solution:

  • 1 1 0 1 1 (initial state);
  • 0 1 1 1 0 (the flipped positions are the first, the third and the fifth elements);
  • 0 0 0 0 0 (the flipped positions are the second, the third and the fourth elements).

Other answers are also possible. In this test the number of operations should not exceed 53+12=1+12=13\lfloor \frac{5}{3} \rfloor + 12 = 1 + 12 = 13 .

In the second sample the only available operation is to flip all the elements. This way it is only possible to obtain the arrays 0 1 0 and 1 0 1, but it is impossible to make all elements equal to zero.

首页