CF1016B.Segment Occurrences

普及/提高-

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题目描述

You are given two strings ss and tt , both consisting only of lowercase Latin letters.

The substring s[l..r]s[l..r] is the string which is obtained by taking characters sl,sl+1,,srs_l, s_{l + 1}, \dots, s_r without changing the order.

Each of the occurrences of string aa in a string bb is a position ii ( 1iba+11 \le i \le |b| - |a| + 1 ) such that b[i..i+a1]=ab[i..i + |a| - 1] = a ( a|a| is the length of string aa ).

You are asked qq queries: for the ii -th query you are required to calculate the number of occurrences of string tt in a substring s[li..ri]s[l_i..r_i] .

输入格式

The first line contains three integer numbers nn , mm and qq ( 1n,m1031 \le n, m \le 10^3 , 1q1051 \le q \le 10^5 ) — the length of string ss , the length of string tt and the number of queries, respectively.

The second line is a string ss ( s=n|s| = n ), consisting only of lowercase Latin letters.

The third line is a string tt ( t=m|t| = m ), consisting only of lowercase Latin letters.

Each of the next qq lines contains two integer numbers lil_i and rir_i ( 1lirin1 \le l_i \le r_i \le n ) — the arguments for the ii -th query.

输出格式

Print qq lines — the ii -th line should contain the answer to the ii -th query, that is the number of occurrences of string tt in a substring s[li..ri]s[l_i..r_i] .

输入输出样例

  • 输入#1

    10 3 4
    codeforces
    for
    1 3
    3 10
    5 6
    5 7
    

    输出#1

    0
    1
    0
    1
    
  • 输入#2

    15 2 3
    abacabadabacaba
    ba
    1 15
    3 4
    2 14
    

    输出#2

    4
    0
    3
    
  • 输入#3

    3 5 2
    aaa
    baaab
    1 3
    1 1
    

    输出#3

    0
    0
    

说明/提示

In the first example the queries are substrings: "cod", "deforces", "fo" and "for", respectively.

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