CF998B.Cutting

There are a lot of things which could be cut — trees, paper, "the rope". In this problem you are going to cut a sequence of integers.

There is a sequence of integers, which contains the equal number of even and odd numbers. Given a limited budget, you need to make maximum possible number of cuts such that each resulting segment will have the same number of odd and even integers.

Cuts separate a sequence to continuous (contiguous) segments. You may think about each cut as a break between two adjacent elements in a sequence. So after cutting each element belongs to exactly one segment. Say, $[4, 1, 2, 3, 4, 5, 4, 4, 5, 5]$ $\to$ two cuts $\to$ $[4, 1 | 2, 3, 4, 5 | 4, 4, 5, 5]$ . On each segment the number of even elements should be equal to the number of odd elements.

The cost of the cut between $x$ and $y$ numbers is $|x - y|$ bitcoins. Find the maximum possible number of cuts that can be made while spending no more than $B$ bitcoins.

First line of the input contains an integer $n$ ( $2 \le n \le 100$ ) and an integer $B$ ( $1 \le B \le 100$ ) — the number of elements in the sequence and the number of bitcoins you have.

Second line contains $n$ integers: $a_1$ , $a_2$ , ..., $a_n$ ( $1 \le a_i \le 100$ ) — elements of the sequence, which contains the equal number of even and odd numbers

Print the maximum possible number of cuts which can be made while spending no more than $B$ bitcoins.

In the first sample the optimal answer is to split sequence between $2$ and $5$ . Price of this cut is equal to $3$ bitcoins.

In the second sample it is not possible to make even one cut even with unlimited number of bitcoins.

In the third sample the sequence should be cut between $2$ and $3$ , and between $4$ and $5$ . The total price of the cuts is $1 + 1 = 2$ bitcoins.