CF954H.Path Counting
普及/提高-
通过率:0%
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题目描述
You are given a rooted tree. Let's denote d(x) as depth of node x : depth of the root is 1 , depth of any other node x is d(y)+1 , where y is a parent of x .
The tree has the following property: every node x with d(x)=i has exactly ai children. Maximum possible depth of a node is n , and an=0 .
We define fk as the number of unordered pairs of vertices in the tree such that the number of edges on the simple path between them is equal to k .
Calculate fk modulo 109+7 for every 1<=k<=2n−2 .
输入格式
The first line of input contains an integer n ( 2<=n<=5000 ) — the maximum depth of a node.
The second line of input contains n−1 integers a1,a2,...,an−1 ( 2<=ai<=109 ), where ai is the number of children of every node x such that d(x)=i . Since an=0 , it is not given in the input.
输出格式
Print 2n−2 numbers. The k -th of these numbers must be equal to fk modulo 109+7 .
输入输出样例
输入#1
4 2 2 2
输出#1
14 19 20 20 16 16
输入#2
3 2 3
输出#2
8 13 6 9
说明/提示
This the tree from the first sample: