CF978F.Mentors
普及/提高-
通过率:0%
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题目描述
In BerSoft n programmers work, the programmer i is characterized by a skill ri .
A programmer a can be a mentor of a programmer b if and only if the skill of the programmer a is strictly greater than the skill of the programmer b (ra>rb) and programmers a and b are not in a quarrel.
You are given the skills of each programmers and a list of k pairs of the programmers, which are in a quarrel (pairs are unordered). For each programmer i , find the number of programmers, for which the programmer i can be a mentor.
输入格式
The first line contains two integers n and k (2≤n≤2⋅105 , 0≤k≤min(2⋅105,2n⋅(n−1))) — total number of programmers and number of pairs of programmers which are in a quarrel.
The second line contains a sequence of integers r1,r2,…,rn (1≤ri≤109) , where ri equals to the skill of the i -th programmer.
Each of the following k lines contains two distinct integers x , y (1≤x,y≤n , x=y) — pair of programmers in a quarrel. The pairs are unordered, it means that if x is in a quarrel with y then y is in a quarrel with x . Guaranteed, that for each pair (x,y) there are no other pairs (x,y) and (y,x) in the input.
输出格式
Print n integers, the i -th number should be equal to the number of programmers, for which the i -th programmer can be a mentor. Programmers are numbered in the same order that their skills are given in the input.
输入输出样例
输入#1
4 2 10 4 10 15 1 2 4 3
输出#1
0 0 1 2
输入#2
10 4 5 4 1 5 4 3 7 1 2 5 4 6 2 1 10 8 3 5
输出#2
5 4 0 5 3 3 9 0 2 5
说明/提示
In the first example, the first programmer can not be mentor of any other (because only the second programmer has a skill, lower than first programmer skill, but they are in a quarrel). The second programmer can not be mentor of any other programmer, because his skill is minimal among others. The third programmer can be a mentor of the second programmer. The fourth programmer can be a mentor of the first and of the second programmers. He can not be a mentor of the third programmer, because they are in a quarrel.