CF938E.Max History
普及/提高-
通过率:0%
AC君温馨提醒
该题目为【codeforces】题库的题目,您提交的代码将被提交至codeforces进行远程评测,并由ACGO抓取测评结果后进行展示。由于远程测评的测评机由其他平台提供,我们无法保证该服务的稳定性,若提交后无反应,请等待一段时间后再进行重试。
题目描述
You are given an array a of length n . We define fa the following way:
- Initially fa=0 , M=1 ;
- for every 2<=i<=n if aM<ai then we set fa=fa+aM and then set M=i .
Calculate the sum of fa over all n! permutations of the array a modulo 109+7 .
Note: two elements are considered different if their indices differ, so for every array a there are exactly n! permutations.
输入格式
The first line contains integer n ( 1<=n<=1 000 000 ) — the size of array a .
Second line contains n integers a1,a2,...,an ( 1<=ai<=109 ).
输出格式
Print the only integer, the sum of fa over all n! permutations of the array a modulo 109+7 .
输入输出样例
输入#1
2 1 3
输出#1
1
输入#2
3 1 1 2
输出#2
4
说明/提示
For the second example all the permutations are:
- p=[1,2,3] : fa is equal to 1 ;
- p=[1,3,2] : fa is equal to 1 ;
- p=[2,1,3] : fa is equal to 1 ;
- p=[2,3,1] : fa is equal to 1 ;
- p=[3,1,2] : fa is equal to 0 ;
- p=[3,2,1] : fa is equal to 0 .
Where p is the array of the indices of initial array a . The sum of fa is equal to 4 .