CF903G.Yet Another Maxflow Problem
普及/提高-
通过率:0%
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题目描述
In this problem you will have to deal with a very special network.
The network consists of two parts: part A and part B . Each part consists of n vertices; i -th vertex of part A is denoted as Ai , and i -th vertex of part B is denoted as Bi .
For each index i ( 1<=i<n ) there is a directed edge from vertex Ai to vertex Ai+1 , and from Bi to Bi+1 , respectively. Capacities of these edges are given in the input. Also there might be several directed edges going from part A to part B (but never from B to A ).
You have to calculate the maximum flow value from A1 to Bn in this network. Capacities of edges connecting Ai to Ai+1 might sometimes change, and you also have to maintain the maximum flow value after these changes. Apart from that, the network is fixed (there are no changes in part B , no changes of edges going from A to B , and no edge insertions or deletions).
Take a look at the example and the notes to understand the structure of the network better.
输入格式
The first line contains three integer numbers n , m and q ( 2<=n,m<=2⋅105 , 0<=q<=2⋅105 ) — the number of vertices in each part, the number of edges going from A to B and the number of changes, respectively.
Then n−1 lines follow, i -th line contains two integers xi and yi denoting that the edge from Ai to Ai+1 has capacity xi and the edge from Bi to Bi+1 has capacity yi ( 1<=xi,yi<=109 ).
Then m lines follow, describing the edges from A to B . Each line contains three integers x , y and z denoting an edge from Ax to By with capacity z ( 1<=x,y<=n , 1<=z<=109 ). There might be multiple edges from Ax to By .
And then q lines follow, describing a sequence of changes to the network. i -th line contains two integers vi and wi , denoting that the capacity of the edge from Avi to Avi+1 is set to wi ( 1<=vi<n , 1<=wi<=109 ).
输出格式
Firstly, print the maximum flow value in the original network. Then print q integers, i -th of them must be equal to the maximum flow value after i -th change.
输入输出样例
输入#1
4 3 2 1 2 3 4 5 6 2 2 7 1 4 8 4 3 9 1 100 2 100
输出#1
9 14 14
说明/提示
This is the original network in the example: