CF1931B.Make Equal

普及/提高-

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题目描述

There are nn containers of water lined up, numbered from left to right from 11 to nn . Each container can hold any amount of water; initially, the ii -th container contains aia_i units of water. The sum of aia_i is divisible by nn .

You can apply the following operation any (possibly zero) number of times: pour any amount of water from the ii -th container to the jj -th container, where ii must be less than jj (i.e. i<ji<j ). Any index can be chosen as ii or jj any number of times.

Determine whether it is possible to make the amount of water in all containers the same using this operation.

输入格式

The first line of the input contains a single integer tt ( 1t1041 \le t \le 10^4 ) — the number of test cases. Then the descriptions of the test cases follow.

The first line of each test case contains a single integer nn ( 1n21051 \le n \le 2 \cdot 10^5 ) — the number of containers with water.

The second line of each test case contains nn integers a1,a2,,ana_1, a_2, \dots, a_n ( 0ai1090 \le a_i \le 10^9 ) — the amounts of water in the containers. It is guaranteed that the sum of aia_i in each test case does not exceed 21092 \cdot 10^9 . Also, the sum of aia_i is divisible by nn .

It is guaranteed that the sum of nn over all test cases in the input does not exceed 21052 \cdot 10^5 .

输出格式

Output tt lines, each of which is the answer to the corresponding test case. As the answer, output "YES" if it is possible to make the amount of water in all containers the same using the described operation. Otherwise, output "NO".

You can output each letter in any case (lowercase or uppercase). For example, the strings "yEs", "yes", "Yes", and "YES" will be accepted as a positive answer.

输入输出样例

  • 输入#1

    6
    1
    43
    2
    1 3
    5
    4 5 2 1 3
    3
    1 2 3
    7
    4 5 5 0 6 4 4
    7
    6 5 5 1 3 4 4

    输出#1

    YES
    NO
    YES
    NO
    NO
    YES

说明/提示

In the third test case of the example ( a=[4,5,2,1,3]a=[4, 5, 2, 1, 3] ), you can proceed as follows:

  • pour 11 unit of water from the first vessel to the fourth, then a=[3,5,2,2,3]a=[3, 5, 2, 2, 3] ;
  • pour 11 unit of water from the second vessel to the third, then a=[3,4,3,2,3]a=[3, 4, 3, 2, 3] ;
  • pour 11 unit of water from the second vessel to the fourth, then a=[3,3,3,3,3]a=[3, 3, 3, 3, 3] .
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